Given:
Temperature in the morning = 6°F.
By the late afternoon, the temperature had dropped 9°F.
To find:
The temperature by the late afternoon.
Solution:
Temperature by the late afternoon = Morning temperature - Dropped temperature
Using the given values and the above formula, we get
Temperature by the late afternoon = 6°F - 9°F
Temperature by the late afternoon = -3°F
Therefore, the temperature by the late afternoon is -3°F.
<span>A ball is thrown at a 30 degree angle above the horizontal with a speed of 10 ft/s. After 0.50s the horizontal component of it's velocity will be the same. In a projectile motion the horizontal component of the velocity is said to be constant. Therefore, it will be equal to the initial velocity.</span>
There are 714 boys in that school, you can cross multiply and divide to find the answer, if you wanna check. The way I wrote it was x (boys) / 1309 = 6/11.
Answer:
dist = 60 mph * (3.5 hrs) = 210 miles
The answer is 210 Miles
Bla bla bla your answer is x=4.95
