Not absolutely sure I understand the question, but should be 120
In order to find zeroes of a function, we will probably want to use our quadratic formula.
-b±√b^2-4(a)(c)/2a
If we know our values, we can plug it in.
Our values:
A=1 (Since there is no number in front of x, it is an assumed 1)
B=17
C=72
Now, We can plug it into our formula.
BE SURE TO PUT PARENTHESIS AROUND ALL TERMS!
-(17)±√(17)^2-4(1)(72)/2(1)
Now we can type it into a calculator!
When we plug it into the formula. It gives us two real solutions (or zeroes) which are represented as:
-8 & -9.
This is an excellent practice for the solution of quadratic equations.
1*36=36 => (1,36)
2*18=36 => (2,18)
3*12=36 => (3,12)
4*9=36 => (4,9)
6*6=36 => (6,6)
9*4=36 => (9,4)
12*3=36 => (12,3)
18*2=36 => (18,2)
36*1=36 => (36,1)
We can see that the sum decreases until the two factors are close (or equal) and then increases again.
The pair of integers with a sum of 20 is therefore (2,18) or (18,2).
