Part can’t get what ya want sooo idk what to tell u sorry not sorry
Answer:
x(85/100)
Step-by-step explanation:
100-15 = 85
x(85/100)
Problema Solution
You have 800 feet of fencing and you want to make two fenced in enclosures by splitting one enclosure in half. What are the largest dimensions of this enclosure that you could build?
Answer provided by our tutors
Make a drawing and denote:
x = half of the length of the enclosure
2x = the length of the enclosure
y = the width of the enclosure
P = 800 ft the perimeter
The perimeter of the two enclosures can be expressed P = 4x + 2y thus
4x + 3y = 800
Solving for y:
........
click here to see all the equation solution steps
........
y = 800/3 - 4x/3
The area of the two enclosure is A = 2xy.
Substituting y = 800/3 - 4x/3 in A = 2xy we get
A = 2x(800/3 - 4x/3)
A =1600x/3 - 8x^2/3
We need to find the x for which the parabolic function A = (- 8/3)x^2 + (1600/3)x has maximum:
x max = -b/2a, a = (-8/3), b = 1600/3
x max = (-1600/3)/(2*(-8/3))
x max = 100 ft
y = 800/3 - 4*100/3
y = 133.33 ft
2x = 2*100
2x = 200 ft
In similar figures, the angle measures are the same but the side lengths are different. So in #4, x = 42. Since all the angles of a quadrilateral added up equal 360, then y is 360-90-90-42=138. For number 5, make sure you match up the sides correctly in your ratio:
. You could cross multiply to get 4x=16, and x = 4, or you could just realize that reducing 4/8 will give you 2/4 and x = 4. Going back to the idea that in similar shapes corresponding angles are the same measure, x in #6 is 63