This is the graph for that
(1) y² + x² = 53
(2) y - x = 5 ⇒ y = x + 5
subtitute (2) to (1)
(x + 5)² + x² = 53 |use (a + b)² = a² + 2ab + b²
x² + 2x·5 + 5² + x² = 53
2x² + 10x + 25 = 53 |subtract 53 from both sides
2x² + 10x - 28 =0 |divide both sides by 2
x² + 5x - 14 = 0
x² - 2x+ 7x - 14 = 0
x(x - 2) + 7(x - 2) = 0
(x - 2)(x + 7) = 0 ⇔ x - 2 = 0 or x + 7 = 0 ⇔ x = 2 or x = -7
subtitute the values of y to (2)
for x = 2, y = 5 + 2 = 7
for x = -7, y = 5 + (-7) = 5 - 2 = 3
Answer: x = 2 and y = 7 or x = -7 and y = 3
2/15 so 13.3% ?
I’m not entirely sure if this is right but I think it’s getting there...
To answer this, you will use the area of 900 square yards to determine the distances between the bases. Each side of the square is 30 yards, so it will be 30 yards from 1st to home and from 1st to 2nd.
The distance from home to 2nd is a diagonal in the square (the hypotenuse).
You will use the Pythagorean Theorem to find this distance.
a^2 + b^2 = c^2
30^2 + 30 ^2 = c^2
900 + 900 + c^2
1800 = c^2
The square root of 1800 is approximately 42.4 yards.
The ball travels approximately 42.4 yards.
Answer:
It took Lydia 12 minutes to run each mile
Step-by-step explanation:
120/10
