All categories

1 year ago

Double somme help please

Mathematics

1 answer:

Lady_Fox [76]1 year ago

7 0

Answer:

looks like a nazi symbol

Step-by-step explanation:

You might be interested in

3. Can a triangle have sides with the given lengths?<br> 8 cm, 7 cm, 9 cm

Cerrena [4.2K]

Answer:yes

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

What would be the critical value for a two-tailed, one-sample t test with 26 degrees of freedom (df = 26) and an alpha level (p

Alika [10]

Answer: The critical value for a two-tailed t-test = 2.056

The critical value for a one-tailed t-test = 1.706

Step-by-step explanation:

Given : Degree of freedom : df= 26

Significance level : $\alpha=0.05$

Using student's t distribution table , the critical value for a two-tailed t-test will be :-

$t_{\alpha/2, df}=t_{0.025,26}=2.056$

The critical value for a two-tailed t-test = 2.056

Again, Using student's t distribution table , the critical value for a one-tailed t-test will be :-

$t_{\alpha, df}=t_{0.05,26}=1.706$

The critical value for a one-tailed t-test = 1.706

6 0

2 years ago

Kedir bout 200 eggs for Birr 50 Birr and sells them for Birr 0.30 each.

ella [17]

Answer:

Yes, Kedir made profit.

Step-by-step explanation:

0.30 x 200 = 60 Birr

60 Birr is more than 50 Birr

He made profit of 10Birr, which is 20% of 50 Birr

8 0

1 year ago

write a function g whose graph represents a translation 2 units to the right followed by a horizontal stretch by a factor or 2 o

Alenkinab [10]

$\bf f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}\\\\
f(x)=&{{ A}} \left|{{ B }}x+{{ C}} \right|+{{ D}}
\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see,

$\bf f(x)=|x| \implies \begin{array}{lllccll}
f(x)=&1|&1x&+0|&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

so, to shift it to the right by 2 units, simply set C = 2.
to stretch it by 2, set A = 1/2.

the smaller A is, the wider it opens, the larger it is, the more it shrinks.

5 0

2 years ago

PLS HELP ME IM ON TIME4LEARNING

alukav5142 [94]

Answer:

Step-by-step explanation:

12*12=144

5*5=25

$\sqrt{169} = 13$

7 0

1 year ago

Read 2 more answers