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1 year ago

9

Determine the elastic energy U stored in the compressed spring.

1 answer:

hoa [83]1 year ago

7 0

Answer:

Answer: The spring constant of the spring is k = 800 N/m, and the potential energy is U = 196 J. To find the distance, rearrange the equation: The equation to find the distance the spring has been compressed is therefore: The spring has been compressed 0.70 m, which resulted in an elastic potential energy of U = 196 J being stored.

Explanation:

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10. How far does a transverse pulse travel in 1.23 ms on a string with a density of 5.47 × 10−3 kg/m under tension of 47.8 ?????

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Answer: Tension = 47.8N, Δx = 11.5× $10^{-6}$ m.

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$\Delta x = |v|.t$

$\Delta x = 9.35.10^{-2}*1.23.10^{-3}$

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$E_{photon}=m_{p}c^2+m_{np}c^2+K.E_{p}+K.E_{np}$

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