The relative frequency of the marked elks are:
- Male Elk = 7/30
- Female Elk = 4/15
- Adult Elk= 173/450
- Baby Elk = 26/22
<h3>How to determine the relative frequency?</h3>
From the complete question, we have:
- Male = 105
- Female = 120
- Adult = 173
- Baby = 52
- Total = 450
The relative frequency of each is then calculated as:
Male Elk = 105/450
Male Elk = 7/30
Female Elk = 120/450
Female Elk = 4/15
Adult Elk= 173/450
Baby Elk = 52/450
Baby Elk = 26/22
<h3>The number of Elks in the park</h3>
Using the data in (a), we can conclude that:
There are 105 male, 120 female, 173 adult, and 26 baby in the park
Read more about frequency table at:
brainly.com/question/1094036
#SPJ1
<h2>
Answer:</h2>
Step 1: Determine the formula.
y - y₁ = m(x - x₁)
Step 2: Determine what variables you need.
(x₁,y₁) = a point on the line
m = slope
Step 3: Plug each number in for the variables and you have the completed point-slope form of the equation for the line.
The point-slope form of this line is: 
.
See the image for the formula I used.
Answer:
<h3>45mL hot cocoa is more chocolatey</h3>
Step-by-step explanation:
When Arjun makes hot cocoa, if he add 20mL of chocolate syrup to 3ounces of water, let us know the equivalent chocolate in one ounces of water.
20mL = 3 ounces
x = 1 ounce
cross multiply
3x = 20
x = 20/3
x = 6.67 mL
This means he must have add 6.67mL of chocolate to 1 ounce of water.
Similarly, if 45mL is added to every 6 ounces
45mL = 6ounces
x = 1 ounce
cross multiply
6x = 45
x = 45/6
x = 7.5mL
This means he must have add 7.5mL of chocolate to 1 ounce of water.
The hot cocoa that is more chocolatey is the one with the highest amount of chocolate in 1 ounce. That is 45mL hot cocoa
Answer:
3
Step-by-step explanation:
f(x) = 3x² - 2x + 1
f(x) = ax² + bx + c
a = 3
Graph C is the reflected image of triangle P
