The pool can hold 65.84 ft³ of water
<u>Explanation:</u>
Given:
Shape of pool = octagonal
Base area of the pool = 22 ft²
Depth of the pool = 3 feet
Volume, V = ?
We know:
Area of octagon = 2 ( 1 + √2) a²
22 ft² = 2 ( 1 + √2 ) a²
a² =
a² = 4.55
a = 2.132 ft
Side length of the octagon is 2.132 ft
We know:
Volume of octagon =
Therefore, the pool can hold 65.84 ft³ of water
Answer:
w=15
Step-by-step explanation:
-24=-3w+21
We move all terms to the left:
-24-(-3w+21)=0
We get rid of parentheses
3w-21-24=0
We add all the numbers together, and all the variables
3w-45=0
We move all terms containing w to the left, all other terms to the right
3w=45
w=45/3
w=15
So we got the real axis and the imaginary axis
we just need to find the average of the 2 points
remember
midpoint of (x1,y1) and (x2,y2) is
((x1+x2)/2,(y1+y2)/2)
so
average of 3 and -8 is -5/2
average of -5i and 2i is -3/2i
center is -5/2-3/2i
Answer: 18+54
Step-by-step explanation:
6*3=18 and 6*9=54
Answer:
C. 20
Step-by-step explanation: