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1 year ago

PLS HELP ME 15 points in total

Mathematics

1 answer:

lilavasa [31]1 year ago

8 0

Answer:

Its 53 because 1=1 and 2=2

Step-by-step explanation:

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Historically, these bolts have an average thickness of 10.1 mm. A recent random sample of 10 bolts yielded these thicknesses:

Akimi4 [234]

Answer:

a) Sample mean = 9.99

Sample standard deviation = 0.3348

b) -1.0389

c) 0.1631

Step-by-step explanation:

We are given the following in the question:

9.7, 9.9, 10.3, 10.1, 10.5, 9.4, 9.9, 10.1, 9.7, 10.3

a) sample mean and standard deviation

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{99.9}{10} = 9.99$

Sum of squares of differences = 1.009

$S.D = \sqrt{\dfrac{1.009}{9}} = 0.3348$

b) observed value of the t-statistic

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{9.99 - 10.1}{\frac{0.3348}{\sqrt{10}} } = -1.0389$

c) probability of these statistics (or worse) if the true mean were 10.1 mm

Degree of freedom = n - 1 = 9

Calculating the value from the table

$P(x < 9.99) = 0.1631$

0.1631 is the the probability of these statistics (or worse) if the true mean were 10.1 mm

8 0

2 years ago

Assume that all grade-point averages are to be standardized on a scale between 0 and 6. How many grade-point averages must be

yanalaym [24]

Answer:

The sample size 'n' = 72,030

Step-by-step explanation:

Step(i):-

Given that the Estimate Error = 0.013

Given that the standard deviation of the Population = 1.5

The estimated error is determined by

$E = \frac{Z_{0.98} S.D }{\sqrt{n} }$

Step(ii):-

Given that the Level of significance = 0.98 or 0.02

Z₀.₀₂ = 2.326

The estimated error is determined by

$E = \frac{Z_{0.98} S.D }{\sqrt{n} }$

$0.013 = \frac{2.326 X 1.5 }{\sqrt{n} }$

$\sqrt{n} = \frac{3.489}{0.013} = 268.38$

Squaring on both sides, we get

n = 72,030

Final answer:-

The sample size 'n' = 72,030

7 0

2 years ago

I am genuinely lost ..... pls dont give me pdfs or links

Nutka1998 [239]

Answer:

There are 60 6th graders in band.

Step-by-step explanation:

Let x represent the number of 6th graders in band. If there are 25% more in 7th grade, you can write it as (5/4)x. (You could also say 1.25x, but I think fractions would be easier in this situation.) Set up an equation:

x+(5/4)x=135

Now solve for x.

(4/4)x+(5/4)x=135

(9/4)x=135

(1/4)x=15

x=60

There are 60 6th graders in band.

Hope I could help you!

3 0

2 years ago

(2x + 3) + (4x + 5) please help im really confused

luda_lava [24]

Answer: it's 6x + 8 if you solve it

8 0

2 years ago

A self-serve frozen yogurt store sells servings up to 12 ounces. It charges $0.50 per ounce for a serving between 0 and 8 ounces

True [87]

Answer:

p(w) - - - - - - p = 0.5w ; for 0 < w ≤ 8

p(w) - - - - - - p = 4 ; for w < 8 and w ≤ 12

Step-by-step explanation:

Price, p of weight of a toughurt serving :

p(w) - - - - - - p = 0.5w ; for 0 < w ≤ 8

p(w) - - - - - - p = 4 ; for w < 8 and w ≤ 12

4 0

2 years ago