Answer:
no I have no answer
Step-by-step explanation:
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In this number 1500,000,
1 is at million place and 5 is at hundred thousand place
So, the value of 1 = 1 (1,000,000) = 1 million
And the value of 5 = 5 (100,000 ) = 500,000 = Five hundred thousand
In the second number 100,500
1 is at hundred thousand place and 5 is at hundred place
The value of 1 = 1 (100,000) = 100,000 = Hundred thousand
And the value of 5 = 5 (100 ) = 500 = Five hundred
Since the digits 1 and 5 both are at different places in both the numbers so 1,500,000 and 100,500 are not the same.
(x-5)(4x+1)
4x^2 times -5 is -20 the factors of -20 are -1x20, 1x-20... but to make the -19x you would add together the 1 and -20 because 1-20 is -19.
This then splits off to factorise 4x^2-20x, making this side 4x(1x-5) carry the brackets over to make it 1(1x-5) joining the brackets together to make (4x+1)(x-5)
Algebra:
A standard parabola is y = x^2. Its vertex is at (0,0)
You can change the position (or vertex) of the parabola.
To move a parabola across the x-axis, you can add or subtract a number from x WITHIN brackets of the ^2
eg. (x + 1)^2 will move the parabola across the x-axis. It will move is one unit to the LEFT (as the sign is opposite to the direction it moves ie. The sign it + but you move the whole parabola in the -ve direction).
Adding or subtracting a number from x OUTSIDE of the ^2 moves the parabola up or down the y-axis
eg. x^2 + 3 will move the parabola UP 3 units (the sign is the same as the direction it moves when the added/subtracted number is outside of the ^2 ie. the sign is positive so the parabola moves up in the positive direction)
From this, we can conclude that because (x + 1)^2 + 3, the vertex will be where x = -1 and where y = 3
Vertex : (-1,3)
Calculus:
f(x) = (x + 1)^2 + 3 = x^2 + 2x + 1 + 3 = x^2 + 2x + 4
Expanding the formular to make it easier to differentiate
f'(x) = 2x + 2
Differentiating (finding the formular the the gradiet of the parabola)
0 = 2x + 2
When the gradient is equal to zero, it must be the vertex
-2 = 2x
-2/2 = x
x = -1
Solve to give the x value at the vertex
f(x) = (x + 1)^2 + 3
= (-1 + 1)^2 + 3
Substitute x = -1 into original equatiom to find y value at the vertex
= (0)^2 + 3
= 0 + 3
= 3
Solve for y
Vertex : (-1,3)