2x - 6y = 12
so we pick any number for x and then solve for y
lets say x = 0
2(0) - 6y = 12
-6y = 12
y = -12/6
y = -2....so when x = 0, y = -2....(0,-2) <== one point
lets say x = 1
2(1) - 6x = 12
2 - 6x = 12
-6x = 12 - 2
-6x = 10
x = -10/6
x = - 5/3...so when x = 1, y = -5/3....(1,-5/3) <== another point
Lets say x = 2
2(2) - 6y = 12
4 - 6y = 12
-6y = 12 - 4
-6y = 8
y = -8/6
y = - 4/3....so when x = 2, y = -4/3.....(2,-4/3) <== another point
lets say x = 3
2(3) - 6y = 12
6 - 6y = 12
-6y = 12 - 6
-6y = 6
y = -6/6
y = -1....so when x = 3, y = -1.....(3,-1) <== another point
now there is 4 points.
78
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0.37
3.4
0.3 repeating
0.02
If the points B , C and D all lie on the line segment AE then AE = AB + CD + DE
Answer:
All raisins would be moving away from you at the same speed, without any dependence
Step-by-step explanation:
As you can see in the graph it is irrelevant if they are on one side or another of the cake since you would see everyone moving away from you at the same speed since the cake must undoubtedly expand to establish a distance of 3cm between the raisins
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Note: It should be understood that the dough should be uniform and the ideal cooking conditions for a standard cake
