Answer:
6 less-than-or-equal-to x less-than infinity
Step-by-step exhplanation:
y = 2(x - 6)^½
x - 6 》0
Because square root of negative values is not real
x - 6》0
x》6
This is the same as:
6《x < infinity
7x+15=38
7x=38-15
7x=23
x=23/7
If you want the answer in point slope form then,
y-y1 = m(x-x1)
y-c = m(x-a)
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If you want the answer in slope intercept form, then solve for y
y-c = m(x-a)
y-c = mx-ma
y-c+c = mx-ma+c
y = mx-ma+c
y = mx+c-ma
y = mx+(c-ma)
For this answer in slope intercept form the slope is m and the y intercept is c-ma
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If you want the answer in standard form, then get the variable terms to the left side. Have the constant terms on the right side.
y = mx+c-ma
y-mx = mx+c-ma-mx
-mx+y = c-ma
Optionally you can multiply both sides by -1 to get mx-y = -c+ma but it will depend on your book if this step is carried out or not.
Steps to solve:
3(x - 1) = 5x + 3 - 2x
~Distribute left side
3x - 3 = 5x + 3 - 2x
~Combine like terms
3x - 3 = 3x - 3
~Subtract 3x to both sides
-3 = -3
~Add 3 to both sides
0 = 0
All real numbers are solutions.
Best of Luck!
