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2 years ago

Find the value of x in the equation below. 5.4=2x

Mathematics

2 answers:

Levart [38]2 years ago

8 0

Answer: x= 2.7

1. Divide 2 on both sides

2. cancel terms who have the same numerator and denominator

adelina 88 [10]2 years ago

7 0

Answer:

x = 2.7

Step-by-step explanation:

5.4 = 2x

2x = 5.4

Divide both sides by 2.

x = 2.7

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In the problem 100 divided by 25 equals 4 the the what is 100

Mekhanik [1.2K]

Answer:

<em>Dividend</em>

Step-by-step explanation:

Dividend is a number that is to be divides by other.

So 100 is a dividend.

25:

A divisor.

A divisor is a number to be divided by.

Result of the division

6 0

3 years ago

Find the value of X below

Paul [167]

Answer: x= 80

Step-by-step explanation:

it’s an isoceles triangle so bottom 2 angles are 50

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7 0

2 years ago

The points (-1, r) and (5, -5) lie on a line with slope - 3. Find the missing coordinate r.

stealth61 [152]

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2 years ago

Evaluate 15/5 + 40 . 7 - 3 to the power of 4.

Lina20 [59]

15/5 + 40.7 -3^4
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4 0

2 years ago

Suppose that an airline uses a seat width of 16.5 in. Assume men have hip breadths that are normally distributed with a mean of

Alexxx [7]

Answer:

a) 0.018

b) 0

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 14.4 in

Standard Deviation, σ = 1 in

We are given that the distribution of breadths is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(breadth will be greater than 16.5 in)

P(x > 16.5)

$P( x > 16.5) = P( z > \displaystyle\frac{16.5 - 14.4}{1}) = P(z > 2.1)$

$= 1 - P(z \leq 2.1)$

Calculation the value from standard normal z table, we have,

$P(x > 16.5) = 1 - 0.982 = 0.018 = 1.8\%$

0.018 is the probability that if an individual man is randomly selected, his hip breadth will be greater than 16.5 in.

b) P( with 123 randomly selected men, these men have a mean hip breadth greater than 16.5 in)

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

P(x > 16.5)

$P( x > 16.5) = P( z > \displaystyle\frac{16.5-14.4}{\frac{1}{\sqrt{123}}}) = P(z > 23.29)$

$= 1 - P(z \leq 23.29)$

Calculation the value from standard normal z table, we have,

$P(x > 16.5) = 1 - 1 = 0$

There is 0 probability that 123 randomly selected men have a mean hip breadth greater than 16.5 in

4 0

2 years ago