Given:
Consider the given expression is:
To find:
The simplified form of the given expression.
Solution:
We have,
Using distributive property, it can be written as:
Therefore, the correct option is A.
Answer:
118.8
Step-by-step explanation:
Profit=10%
=10/100 × $132
=$13.2
Cost price=Selling price- Cost price
=$132-$13.2
=$118.8
Answer:
113
Step-by-step explanation:
Let the number of adult tickets sold =a
Let the number of student tickets sold =s
A total of 259 tickets were sold, therefore:
a+s=259
Adult tickets were sold for $24 each and student tickets were sold for $16 each.
Total Revenue = $5,312
Therefore:
24a+16s=5,312
We solve the two derived equations simultaneously.
From the first equation
a=259-s
Substitute a=259-s into 24a+16s=5,312
24(259-s)+16s=5,312
6216-24s+16s=5,312
-8s=5,312-6216
-8s=-904
Divide both sides by -8
s=113
Therefore, 113 student tickets were sold.
First, you have to substitute for x, which would make the problem f(x)=7.45(-4.3)+33.7
Now, you just have to use the PEMDAS method (Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction)
f(x)= -32.035+33.7
f(x)=1.665
Answer:
0.000064 = 0.0064% probability that the box will contain less than the advertised weight of 466 g.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation , the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
N(489,6)
This means that
What is the probability that the box will contain less than the advertised weight of 466 g?
This is the p-value of Z when X = 466. So
has a p-value of 0.000064
0.000064 = 0.0064% probability that the box will contain less than the advertised weight of 466 g.