Answer:
Given that,
The number of grams A of a certain radioactive substance present at time, in years
from the present, t is given by the formula
a) To find the initial amount of this substance
At t=0, we get
We know that e^0=1 ( anything to the power zero is 1)
we get,
The initial amount of the substance is 45 grams
b)To find thehalf-life of this substance
To find t when the substance becames half the amount.
A=45/2
Substitute this we get,
Taking natural logarithm on both sides we get,
Half-life of this substance is 154.02
c) To find the amount of substance will be present around in 2500 years
Put t=2500
we get,
The amount of substance will be present around in 2500 years is 0.000585 grams
A trapezoid with legs MN = FD is an isosceles trapezoid.
An isosceles trapezoid has diagonals that are congruent, therefore: MF = ND.
A quadrilateral with diagonals congruent and perpendicular is a square.
In a square, the height coincides with the side.
The area of a square is given by A = s²
Therefore, the area of MNFD is h²
Answer:
2 11/14 squared feet
Step-by-step explanation:
Area of a rectangle = length x width
Give length = 3 1/4 and
Width = 3/4
Therefore,
Area = 3 1/4 x 3/4
Change the mixed size fraction to an improperly fraction
We have A = 13/4 x 3/4
39/14
2 11/14 squared feet
Answer:
a. $ 2,431.01 = 4 years
b. $ 4,584.04 = 17 years
c. 4.57 years = $ 2,499.57
d. 8.3 year = $ 2,998.48
e. $ 2,431.01 = 4 years
Step-by-step explanation:
Compound Interest Equation
A = P(1 + r/n)nt
Where:
A = Accrued Amount (principal + interest)
P = Principal Amount
I = Interest Amount
R = Annual Nominal Interest Rate in percent
r = Annual Nominal Interest Rate as a decimal
r = R/100
t = Time Involved in years, 0.5 years is calculated as 6 months, etc.
n = number of compounding periods per unit t; at the END of each period