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2 years ago

14

Help me with this please!!!!!!!!!!!!!!!!

1 answer:

olga55 [171]2 years ago

6 0

Answer:

what do you need help with?

Explanation:

I would look up the periodic table of elements

hope this helps!

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Write a numerical expression for the emissive intensity (in W/m^2.sr) coming out of a tiny hole in an enclosure of surface tempe

stiks02 [169]

Answer:

6.0 × $10^{11}$ W/ $m^{2}$

Explanation:

From Wien's displacement formula;

Q = e A $T^{4}$

Where: Q is the quantity of heat transferred, e is the emissivity of the surface, A is the area, and T is the temperature.

The emissive intensity = $\frac{Q}{A}$ = e $T^{4}$

Given from the question that: e = 0.6 and T = 1000K, thus;

emissive intensity = 0.6 × $(1000)^{4}$

= 0.6 × 1.0 × $10^{12}$

= 6.0 × $10^{11}$ $\frac{W}{m^{2} }$

Therefore, the emissive intensity coming out of the surface is 6.0 × $10^{11}$ W/ $m^{2}$ .

3 0

2 years ago

State the name given to the energy that is needed to melt the ice cube: latent __________.

Vaselesa [24]

Answer:

Explanation: heat of fusion

5 0

2 years ago

Which robotic missions studied Venus?

frosja888 [35]

The first successful flyby of Venus was performed by NASA's Mariner 2 spacecraft on 14 December 1962, following failed attempts by both the Soviet Union and the USA. The first successful landing was the Soviet Venera 4 lander, which touched down on the surface on 18 October 1967

6 0

2 years ago

Read 2 more answers

Water with a volume flow rate of 0.001 m3/s, flows inside a horizontal pipe with diameter of 1.2 m. If the pipe length is 10m an

galben [10]

Answer:

$\triangle P=1.95*10^{-4}$

Explanation:

Mass $m=0.001$

Diameter $d=1.2m$

Length $l=10m$

Generally the equation for Volume flow rate is mathematically given by

$Q=AV$

$V=\frac{Q}{\pi/4D^2}$

$V=\frac{0.001}{\pi/4(1.2)^2}$

$V=8.84*10^{-4}$

Generally the equation for Friction factor is mathematically given by

$F=\frac{64}{Re}$

Where Re

Re=Reynolds Number

$Re=\frac{pVD}{\mu}$

$Re=\frac{1000*8.84*10^{-4}*1.2}{1.002*10^{-3}}$

$Re=1040$

Therefore

$F=\frac{64}{Re}$

$F=\frac{64}{1040}$

$F=0.06$

Generally the equation for Friction factor is mathematically given by

$Head loss=\frac{fLv^2}{2dg}$

$H=\frac{0.06*10*(8.9*10^-4)^2}{2*1.2*9.81}$

$H=19.9*10^{-9}$

Where

$H=\frac{\triangle P}{\rho g}$

$\triangle P=\frac{19.9*10^{-9}}{10^3*(9.81)}$

$\triangle P=H*\rho g$

$\triangle P=1.95*10^{-4}$

6 0

2 years ago

A chair of mass 12.0 kg is sitting on the horizontal floor; the floor is not frictionless. You push on the chair with a force F

yarga [219]

Answer:

Explanation:

mass, m = 12 kg

Force, F = 40 N

θ = 37° below the horizontal

(a)

Diagram is attached

(b) Let N be the normal reaction

According to the diagram

N + F Sin θ = m g

N = mg - F Sin θ

N = 12 x 9.8 - 40 x Sin 37

N = 117.6 - 24.07

N = 93.53

6 0

2 years ago