For question 11, you essentially need to find when h(t) = 0, since that is when the height of the ball reaches 0 (ie touches the ground).
For question 12, it is asking for a maximum height, so you need to find when dh/dt = 0 and taking the second derivative to prove that there is maximum at t. That will find you the time at which the ball will hit a maximum height.
Rinse and repeat question 12 for question 13
22000=15000(1+.089/4)^4t
22/15=(1.02225)^4t
log(22/15)=4tlog1.02225
(log(22/15)/4log1.02225)=t
(.16633/.038228)=t
t=4.35 years or 4 years and approximately 4 months
Answer:
H. 260
Step-by-step explanation:
We'll begin this problem by first figuring out how many students will be able to sit at the first fourteen tables.
14 tables * 14 students = total students
196 = total students ( for those fourteen tables)
Now we also know that sixteen students can sit on the rest of the cafeteria tables.
We need to find the number of tables can hold sixteen students.
To do this, we'll lead with a simple equation:
18 tables total - 14 tables = # of remaining tables
4 = # of remaining tables
Now we're going to do the same thing we did with the original tables:
4 tables * 16 students = total students
64 = total students
Finally, we add both of the tables max values together:
64 + 196 = 260
Answer :E) Not enough information is given to determine the probability.
Step-by-step explanation:
Le A denotes the event that households in the United States own dogs .
and B denotes the event that households in the United States own cats.
As per given , we have
P(A)=36.5%= 0.365
P(B)=30.4% = 0.304
To find the probability that the selected household will own a dog or a cat, we apply the following formula :
P(A or B)=P(A)+P(B)+P(A and B)
But P(A and B) is not given to us.
i..e the probability that a house hold own both a cat and adg is not given to us.
Therefore, The correct option is (E) Not enough information is given to determine the probability.