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2 years ago

Provide 3 examples of substances that are mixtures and list the substances in them

Chemistry

2 answers:

swat322 years ago

7 0

Answer:

Explanation:

Sand and water - heterogeneous

Sugar and salt - heterogeneous

Ethanol in water - homogenous mixture

Vedmedyk [2.9K]2 years ago

3 0

Answer:

Water and salt = salt water

Oxygen and water = sea foam

Smoke and fog = smog

Explanation:

Hope this helped, nya~ :3

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How do you figure out molality

hodyreva [135]

*The molality of a solution is calculated by taking the moles of solute and dividing by
the kilograms of solvent* Basically if we had 1.00 mole of sucrose (it's about 342 3 grams) and
proceeded to mix it into exactly 1.00 liter water. It would dissolve and make sugar
water. We keep adding water, dissolving and stirring until all the solid was gone. We
then made sure everything was well-mixed.
What would be the molality of this solution? Notice that my one liter of water weighs
1000 grams (density of water = 1.00 g / mL and 1000 mL of water in a liter).

3 0

1 year ago

The equilibrium constant in terms of pressure. Kp for the following process is 0.179 at 50 °C. It increases to 0.669 at 86 °C. C

Vikentia [17]

Answer:

a) ΔHvap=35.3395 kJ/mol

b) Tb=98.62 °C

Explanation:

Given the reaction:

C₇H₁₆ (l) ⇔ C₇H₁₆ (g)

Kp=P(C₇H₁₆) since the concentration ratio for a pure liquid is equal to 1.

When

T₁=50°C=323.15K ⇒P₁=0.179

T₂=86°C=359.15K ⇒P₂=0.669

The Clasius-Clapeyron equation is:

$ln(\frac{P_2}{P_1}) =-\frac{AH_{vap}}{R} (\frac{1}{T_2}-\frac{1}{T_1})$

$ln(\frac{0.669}{0.179}) =-\frac{AH_{vap}}{8.3145 J.mol^{-1}K^{-1}} (\frac{1}{359.15K}-\frac{1}{323.15K})$

$1.3184 =-\frac{AH_{vap}}{8.3145 J.mol^{-1}K^{-1}} (-3.10186*10^{-4}K{^-1})$

ΔHvap=35339.5 J/mol=35.3395 KJ/mol

Normal boiling point ⇒ P=1 atm

Hence, we find the normal boiling point where:

T₁=323.15K

P₁=0.179 atm

P₂=1 atm

$ln(\frac{P_2}{P_1}) =-\frac{AH_{vap}}{R} (\frac{1}{T_2}-\frac{1}{T_1})$

$ln(\frac{1atm}{0.179atm}) =-\frac{35339.5 J/mol}{8.3145 J.mol^{-1}K^{-1}} (\frac{1}{T_2}-\frac{1}{323.15K})$

$1.7203=-4250.34 (\frac{1}{T_2}-\frac{1}{323.15K})$

T₂=371.77 K= 98.62 °C

5 0

2 years ago

WILL GIVE BRAINLIEST. How does Earth's distance from the sun make it advantageous for supporting life?

Goryan [66]

<span>allows for regular periods of sunlight</span>

8 0

3 years ago

NEED HELP!!!

Vilka [71]

Answer:

1.atomic number

2.electron

3.element

4.atom

5.neutron

6.nucleus

7.proton

Explanation:

please like and Mark as brainliest

6 0

2 years ago

Carbon atoms naturally bond with each other in chains, rings, or networks, but they cannot bond with oxygen or nitrogen

mamaluj [8]

False

Explanation:

Carbon atoms are found in hydrocarbons, naturally occurring compound with carbon and hydrogen, but there are molecules in nature that contain beside carbon and hydrogen, oxygen and nitrogen too. In this compounds there are carbon-oxygen and carbon-nitrogen covalent bonds.

Bellow you may see the chemical structure of adrenaline, a hormon found in the human body, were the oxygen (red) and nitrogen (blue) are bonded to carbon.

Learn more about:

structure of organic compounds

brainly.com/question/14118299

#learnwithBrainly

8 0

2 years ago

Read 2 more answers