Factors of 9: 1; 3; 9
Factors of 36: 1; 2; 3; 4; 6; 9; 12; 18; 36
GCF(9; 36) = 9
Answer:
z= 3.63
z for significance level = 0.05 is ± 1.645
Step-by-step explanation:
Here p = 42% = 0.42
n= 500
We formulate our null and alternative hypotheses as
H0: p= 0.42 against Ha : p> 0.42 One tailed test
From this we can find q which is equal to 1-p= 1-0.42 = 0.58
Taking p`= 0.5
Now using the z test
z= p`- p/ √p(1-p)/n
Putting the values
z= 0.5- 0.42/ √0.42*0.58/500
z= 0.5- 0.42/ 0.0220
z= 3.63
For one tailed test the value of z for significance level = 0.05 is ± 1.645
Since the calculated value does not fall in the critical region we reject our null hypothesis and accept the alternative hypothesis that more than 42% people owned cats.
Answer:y=0.5x+10
Step-by-step explanation:
need help with explanation?
Answer:Oof your stuff looks hard!
Step-by-step explanation:
Answer:
{4}
Step-by-step explanation:
It is helpful to let a calculator or spreadsheet perform the function evaluations for you. The two functions have the same value only for x=4 in the domain.
f(4) = 13 = g(4)
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The functions also have the same value for x=-2, but that is not in the domain given.
