Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.
We are to find the probability of selecting 1 red apple and 2 yellow apples.
Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.
Then, we have
Therefore, the probability of event A is given by
Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
Answer: 58.666666666667
Step-by-step explanation:
my brain
Answer:
yall werid
Step-by-step explanation:
Answer:
C. 5 goes into 100 twenty times, and 1 times 20 is 20
Step-by-step explanation:
Since, we know that when we multiply both numerator and denominator of a fraction by a same number then we obtain an equivalent fraction,
Here, the given fraction,
By the above statement,
Now,
Hence,
Option C is correct.
74% means 0.74
"of" means "times"
So, 128 = 0.74 times (the number)
Divide each side of this equation by 0.74 :
128/0.74 = the number
<em>172.973</em> (rounded) = the number