The answer is D. SAS, ASA, and SSS show congruent triangles.
The current area is 15 x 9 = 135 square feet.
He wants to increase both the length and width by X:
Set up an equation:
(15 +x) * (9 +x) = 135 * 2
Simplify :
x^2 + 24x + 135 = 270
Subtract 270 from both sides:
x^2 + 24x - 135 = 0
Use the quadratic formula to solve for x:
-24 +/- √(24^2 - 4(1*-135) / 2*1
x = 4.7 or -28.7
The answer has to be a positive value, so x = 4.7 feet.
Answer:
C. ∠SRT≅∠VTR and ∠STR≅∠VRT
Step-by-step explanation:
Given:
Quadrilateral is a parallelogram.
RS║VT; RT is an transversal line;
Hence By alternate interior angle property;
∠SRT≅∠VTR
∠STR≅∠VRT
Now in Δ VRT and Δ STR
∠SRT≅∠VTR (from above)
segment RT= Segment RT (common Segment for both triangles)
∠STR≅∠VRT (from above)
Now by ASA theorem;
Δ VRT ≅ Δ STR
Hence the answer is C. ∠SRT≅∠VTR and ∠STR≅∠VRT
Answer: w<-9 With the line underneath
Step-by-step explanation:
1 ft = 12 inches....so 4 ft = (4 * 12) = 48 inches
ratio is : 48 to 15...or 48/15 or 48:15......which reduces to 16/5 in lowest terms