Answer:
The best estimate of the depth of the well is 2.3 sec.
Explanation:
Given that,
Record time,
We need to find the best estimate of the depth of the well
According to record time,
We can write of the record time
Here, all time is nearest 2.3 sec.
So, we can say that the best estimate of the depth of the well is 2.3 sec.
Hence, The best estimate of the depth of the well is 2.3 sec.
Supposing the runner is condensed to a point and moves upward at 2.2 m/s.
It takes a time = 2.2/g = 2.2/9.8 = 0.22 seconds to increase to max height.
Now looking at this condition in opposite - that is the runner is at max height and drops back to earth in 0.22 s (symmetry of this kind of motion).
From what height does any object take 0.22 s to fall to earth (supposing there is no air friction)?
d = 1/2gt²= (0.5)(9.8)(0.22)²= 0.24 m
Answer:
1.5m
Explanation:
Speed of waves is given as the product of the wavelength and frequency. Sometimes when frequency is not given but the period is given, we get the frequency as the reciprocal of the period. The speed of waves is given in m/s, wavelength in m while frequency in Hz.
Speed, s= fw and making w the subject of formula,
Substituting 300, 000, 000 m/s for s and 200, 000, 000 for f then we obtain that
Answer:
A
Explanation:
The compressor receive hot refrigerant and raises the pressure and temperature even further as it is send to the condenser.
The sun's intensity for an outer planet located at a distance 6r from the sun is 5.55 W/m². The result is obtained by using the inverse square law formula.
<h3>What is the Inverse Square Law formula?</h3>
The Inverse Square Law formula describes the intensity of light is inversely proportional to the square of the distance. It can be expressed as
Where
- I₁ = Intensity at distance 1 (W/m²)
- I₂ = Intensity at distance 2 (W/m²)
- d₁ = distance 1 from a light source (m)
- d₂ = distance 2 from a light source (m)
Given the case the sun's intensity is 200 W/m² for an inner planet at the distance r. If an outer planet is at a distance 6r, what is the sun's intensity?
By using the inverse square law formula, the sun's intensity for an outer planet is
I₂ = 5.55 W/m²
Hence, the sun's intensity for a planet at a distance 6r from the sun is 5.55 W/m².
Learn more about intensity of light here:
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