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2 years ago

8

In the accompanying diagram, lines a and b are parallel, and lines c and d are transversals. 5 a 6 3 4 7/8 be Which angle is con

gruent to angle 8? A 6
B 5
C 3
D 4

1 answer:

OLga [1]2 years ago

7 0

Answer:

Step-by-step explanation:

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Two forces with magnitudes of 100 and 50 pounds act on an object at angles of 50° and 160°, respectively. Find the direction and

shusha [124]

Forces in direction x:
fx1 = 100 * cos (50) = 64.28
fx2 = 50 * cos (160) = - 46.99
The resultant is:
fx = fx1 + fx2 = 17.29

Forces in direction y:
fy1 = 100 * sine (50) = 76.60
fy2 = 50 * sine (160) = 17.10
The resultant is:
fy = fy1 + fy2 = 93.70
The magnitude of the resulting force is:
f = root (fx ^ 2 + fy ^ 2)
f = root ((17.29) ^ 2 + (93.70) ^ 2)
f = 95.28
The angle is:
theta = atan (fy / fx)
theta = atan (93.70 / 17.29)
theta = 79.55 degrees
Answer:
The direction and magnitude of the resultant force are:
f = 95.28 pounds at theta = 79.55 degrees

6 0

2 years ago

Please help me answer this question

sergejj [24]

Answer:

72km

Step-by-step explanation:

alex : tomos : annabelle = 2 : 3 : 4

if tomos drove 24km

tomos ratio is 3

so 3 --> 24

<em>1 --> 8 </em>

<u>total ratios --> 2 + 3 + 4 = 9</u>

so total journey is 9 --> 9 * 8 = 72km

6 0

1 year ago

Help!! Answer !!! about to run out of time in test!!

Gemiola [76]

$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

Here's the solution ~

Let's find the measure of hypotenuse first, by using Pythagoras theorem ;

$\qquad \sf \dashrightarrow \: h {}^{2} = {8}^{2} + {6}^{2}$

$\qquad \sf \dashrightarrow \: h {}^{2} = {36}^{} + {64}^{}$

$\qquad \sf \dashrightarrow \: h {}^{2} = 100$

$\qquad \sf \dashrightarrow \: h {}^{} = \sqrt{100}$

$\qquad \sf \dashrightarrow \: h {}^{} = {10}$

Now, let's find the asked values ~

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{opposite \: side}{hypotenuse}$

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{6}{10}$

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{3}{5} \: or \: 0.6 \: units$

For Cos y :

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{adjcant \: side}{hypotenuse}$

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{6}{10}$

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{3}{5} \: or \: 0.6 \: units$

As we can see that both sin x and Cos y have equal values, therefore The required relationships is equality.

I.e Sin x = Cos y

Hope it helps ~

3 0

2 years ago

What is 503 rounded to the nearest hundred

yawa3891 [41]

500 is the answer because 500 is much closer

3 0

2 years ago

Use the quadratic formula to solve x² + 9x + 10 = 0.<br><br> What are the solutions to the equation?

jok3333 [9.3K]

Answer:

$-1.30\ and\ -7.70$ (2 decimal places)

Step-by-step explanation:

Quadratic Formula: $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

-----------------------------------------------

$x^2+9x+10=0$

Plug in values:

$x=\frac{-9\pm \sqrt{9^2-4\cdot \:1\cdot \:10}}{2\cdot \:1}$

First value of x:

$x=\frac{-9+\sqrt{41}}{2}=-1.30$ (2 decimal places)

Second value of x:

$x=\frac{-9-\sqrt{41}}{2}=-7.70$ (2 decimal places)

6 0

2 years ago