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2 years ago

(20pts) I need to know who is incorect and why

Mathematics

1 answer:

svp [43]2 years ago

6 0

Answer:

i thig it is hj

Step-by-step explanation:

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6.493 rounded to the hundredths

Nana76 [90]

The answer is 6. 49 you welcome :)

7 0

2 years ago

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What is the coefficient of x2y3 in the expansion of (2x + y)5?

Zigmanuir [339]

Option C:

The coefficient of $x^{2} y^{3}$ is 40.

Solution:

Given expression:

$(2 x+y)^{5}$

Using binomial theorem:

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here $a=2 x, b=y$

Substitute in the binomial formula, we get

$(2x+y)^5=\sum_{i=0}^{5}\left(\begin{array}{l}5 \\i\end{array}\right)(2 x)^{(5-i)} y^{i}$

Now to expand the summation, substitute i = 0, 1, 2, 3, 4 and 5.

$$=\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}+\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1}+\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}+\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}$

$$+\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}+\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}$

Let us solve the term one by one.

$$\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}=32 x^{5}$

$$\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1} = 80 x^{4} y$

$$\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}= 80 x^{3} y^{2}$

$$\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}= 40 x^{2} y^{3}$

$$\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}= 10 x y^{4}$

$$\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}=y^{5}$

Substitute these into the above expansion.

$(2x+y)^5=32 x^{5}+80 x^{4} y+80 x^{3} y^{2}+40 x^{2} y^{3}+10 x y^{4}+y^{5}$

The coefficient of $x^{2} y^{3}$ is 40.

Option C is the correct answer.

5 0

2 years ago

Write an inequality for the sentence below and then solve and check it. The sum of w and nine is less than 18

Andre45 [30]

Answer:

w < 9

Step-by-step explanation:

w + 9 < 18

To solve this inequality, we MUST get the w by itself

Subtraction Property of Equality w + 9 - 9 < 18 - 9

Answer w < 9

7 0

2 years ago

Please simplify 6d²(-7d)

andrew-mc [135]

Simplifying-
(6d^2)(-7d)=
= -(42d^2)(d)
=-42d^3

6 0

2 years ago

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Three boys, Adam, Kyle, and Ty, and two girls, Anne and Kate, have volunteered to help plan the school dance. One student will b

Karo-lina-s [1.5K]

Answer:

2:4

Step-by-step explanation: Subtract 1 from total amount then find the number of girls I think sorry

3 0

1 year ago