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2 years ago

Warm-Up

Mathematics

1 answer:

Sveta_85 [38]2 years ago

4 0

Answer:

Graph # 3

Step-by-step explanation:

-2x + 5y > 15 Let x = 0 solve for y

-2(0) + 5y = 15 change the > to an =

5y = 15

y =3 Point (0, 5) is on the graph

Graph # 3 is correct because the y-intercept is 5

x y

0 3 -2(0) + 5y = 15; 5y = 15

5 5 -2(5) + 5y = 15; -10 + 5y = 15; 5y = 25; y = 5

10 7 -2(10) + 5y = 15; -20 + 5y = 15; 5y = 35; y = 7

The graph > the line is dotted and you will shade above the line

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For the graphed function f(x) = -(5)* - 3 + 2, calculate the average rate of change from x = 3 to x = 4.

Ilia_Sergeevich [38]

Answer:

-4

Step-by-step explanation:

The average rate of change from x=a to x=b of f(x) is $\frac{f(b)-f(a)}{b-a}$

The given function is $f(x)=-5^{x-3}+2$ .

$f(4)=-5^{4-3}+2=-3$ .

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The average rate of change from x=3 to x=4 is given by:

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2 years ago

Simplify.

UkoKoshka [18]

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2 years ago

Using the distance formula, calculate how far Tre threw the ball. (4 points: 2 points for setup, 1 for calculation, 1 for the an

sergij07 [2.7K]

Answer:

$D = 63.717$

Step-by-step explanation:

The details that complete the question are:

$(x_1,y_1) = (0,42.78)$

and

$(x_2,y_1)=(90,42.78)$

Required

Determine how far the ball travelled

Distance is calculated using:

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute values for x's and y's

$D = \sqrt{(42.78 - 0)^2+(42.78-90)^2}$

$D = \sqrt{42.78^2+(-47.22)^2$

$D = \sqrt{1830.1284+2229.7284$

$D = \sqrt{4059.8568$

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2 years ago

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2 years ago

Read 2 more answers

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erica [24]

Answer:

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8 0

1 year ago