Answer: (2x + 3) • (x-1)
Step-by-step explanation:
1 Pull out like factors :
4x + 6 = 2 • (2x + 3)
STEP
3
:
Pulling out like terms
3.1 Pull out like factors :
(5x - 5) = 5 • (x - 1)
The change of displacement with respect to time is defined as speed. Velocity is a vector quantity. The instantaneous velocity at t = 2 is -12.
<h3>What is velocity?</h3>
The change of displacement with respect to time is defined as Velocity. velocity is a vector quantity. It is a time-based component. Its standard unit is m/sec.
Given that the position of an object at time t is given by s(t) = 1 - 12t. Therefore, the velocity of the object can be written as,
V = ds/dt
= d(1 - 12t)/dt
= -12
s'(t) = -12
Now, the instantaneous velocity at t=2 is,
s'(2) = -12
Hence, the instantaneous velocity at t = 2 is -12.
To learn more about Velocity:
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Answer:
0.21
Step-by-step explanation:
if you write it as a fraction it would be 21/100
and if that is made to a decimal it would be 0.21 .
Answer:
0.1587
Step-by-step explanation:
Let X be the commuting time for the student. We know that 
. Then, the normal probability density function for the random variable X is given by
![f(x) = \frac{1}{\sqrt{2\pi(5)^{2}}}\exp[-\frac{(x-\mu)^{2}}{2(5)^{2}}]](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%7B2%5Cpi%285%29%5E%7B2%7D%7D%7D%5Cexp%5B-%5Cfrac%7B%28x-%5Cmu%29%5E%7B2%7D%7D%7B2%285%29%5E%7B2%7D%7D%5D)
. We are seeking the probability P(X>35) because the student leaves home at 8:25 A.M., we want to know the probability that the student will arrive at the college campus later than 9 A.M. and between 8:25 A.M. and 9 A.M. there are 35 minutes of difference. So,
= 0.1587
To find this probability you can use either a table from a book or a programming language. We have used the R statistical programming language an the instruction pnorm(35, mean = 30, sd = 5, lower.tail = F)
Answer: C
It’s going down by the same rate of change, 2.
