The answer to this is the first one (V-shaped graph)
Answer: The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is 0.596
Step-by-step explanation:
Since the weights of catfish are assumed to be normally distributed,
we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = weights of catfish.
µ = mean weight
σ = standard deviation
From the information given,
µ = 3.2 pounds
σ = 0.8 pound
The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is is expressed as
P(x ≤ 3 ≤ 5.4)
For x = 3
z = (3 - 3.2)/0.8 = - 0.25
Looking at the normal distribution table, the probability corresponding to the z score is 0.401
For x = 5.4
z = (5.4 - 3.2)/0.8 = 2.75
Looking at the normal distribution table, the probability corresponding to the z score is 0.997
Therefore,.
P(x ≤ 3 ≤ 5.4) = 0.997 - 0.401 = 0.596
Answer:
3x^2 +6x +4
Step-by-step explanation:
5x ^ 2 + 2x + 11 - 7 + 4x - 2x ^ 2
Combine like terms
5x ^ 2- 2x ^ 2 + 2x + 4x + 11 - 7
3x^2 +6x +4
The y intercept is -2. There is two x- intercepts because it is a parabola so,
x=-1
x=2
The axis of symmetry is where it splits evenly so, we can conclude it is less than 1 and bigger than 0. I hope this makes sense.
26:100
..............................