The chart shows data for a moving object.

White raven [17]

Well, you should TAKE COVER UNDER A STUDY DESK, TABLE OR AGAINST AN INSIDE WALL. Which is C. This is because, doing this protects you from the falling objects. If you do A or B, you will probably get crushed by falling objects because you are exposed. Hope I helped.

3 0

2 years ago

Read 2 more answers

The resistance (R) of a copper wire varies directly as its length (L). Write this relation as a formula using k as the constant

Drupady [299]

Answer:

Explanation:

According to ohm's law current flowing in a conductor is directly proportional to the voltage applied across two end of conductor.

i.e. $V\propto R$

$V=R I$

where R=resistance

$R\propto L$

$R\propto \frac{1}{d^2}$

whee L and d are length and Diameter

thus $R=k \frac{L}{d^2}$

where k=constant of Variation

6 0

2 years ago

A straight wire of length 0.53 m carries a conventional current of 0.2 amperes. What is the magnitude of the magnetic field made

olga55 [171]

Explanation:

It is given that,

Length of wire, l = 0.53 m

Current, I = 0.2 A

(1.) Approximate formula:

We need to find the magnitude of the magnetic field made by the current at a location 2.0 cm from the wire, r = 2 cm = 0.02 m

The formula for magnetic field at some distance from the wire is given by :

$B=\dfrac{\mu_oI}{2\pi r}$

$B=\dfrac{4\pi \times 10^{-7}\times 0.2\ A}{2\pi \times 0.02\ m}$

B = 0.000002 T

$B=10^{-5}\ T$

(2) Exact formula:

$B=\dfrac{\mu_oI}{2\pi r}\dfrac{l}{\sqrt{l^2+4r^2} }$

$B=\dfrac{\mu_o\times 0.2\ A}{2\pi \times 0.02\ m}\times \dfrac{0.53\ m}{\sqrt{(0.53\ m)^2+4(0.02\ m)^2} }$

B = 0.00000199 T

or

B = 0.000002 T

Hence, this is the required solution.

4 0

2 years ago

un bus sale de florencia hacia el municipio de san vicente del caguan con una velocidad de 30km/h. 2 horas mas tarde sale otro b

goldenfox [79]

Recuerda que distancia=velocidad x tiempo ( $d=vt$ ). vamos a llamar $d _{1}$ a la distancia que reccore el primer bus, y $d _{2}$ la distancia que recoore el segundo. Los se econtraran cuando la ditancia recorrida por cada bus sea la misma, es decir $d _{1} =d _{2}$ .
Ahora sabemos que la velocidad del primer bus es 30 km/h y su tiempo es $t$ ; en cuanto al segundo bus, su velocidad es 45 km/h y como sale 2 horas mas tarde su tiempo será $t-2$ . Ahora podemos reemplazar los valores en nuestra ecuación de de distanica para hallar el tiempo:
$30t=45(t-2)$
$30t=45t-90$
$30t-45t=-90$
$-15t=-90$
$t= \frac{-90}{-15}$
$t=6$
Los buses se encontraran en 6 horas, 4 horas después de haber salido el segundo bus.

Ahora para hallar la distancia a la que los buses estaran de <span>san vicente del caguan solo necesitaremos reemplazar la el tiempo en nuestra equación de distancia para el primer bus:
</span> $d _{1} =(30)(6)$
$d _{1} =180$
<span>En el punto de encuentro los buses estarán a 180 km de San Vicente del Caguan.
</span>

7 0

2 years ago

A box is pulled to the right with a force of 65 n at an angle of 58 degrees to the horizontal the surface of frictional is the F

umka21 [38]

Answer:

The force acting in x direction is 34.44 N

Explanation:

We have,

Force acting on the box is 65 N at an angle of 58 degrees to the horizontal the surface of frictional.

It is required to find the net force in x- direction.

The net force acting in the x- direction is given by :

$F_x=F\cos\theta\\\\F_x=65\times \cos(58)\\\\F_x=34.44\ N$

So, the force acting in x direction is 34.44 N.

4 0

2 years ago