Answer:
Step-by-step explanation:
We have given:
x^4-2/x+1
Put x+1 = 0
x= 0-1
x= -1
-1 | 1 0 0 0 -2
| -1 1 -1 1
_______________
1 -1 1 -1 -1
Thus it makes the expression:
x^3-x^2+x-1 - 1/x+1
You can further confirm this expression by solving the expression:
(x4 − 2) ÷ (x + 1).
x^4 - 1 -1/x+1
x^4-1/x+1 - 1/x+1
(x^2-1) (x^2+1)/x+1 - 1/x+1
(x-1)(x+1) (x^2+1)/x+1 - 1/x+1
x+1 n the numerator will be cancelled out by x+1 in the denominator.
(x-1) (x^2+1) - 1/x+1
Multiply (x^2+1) by x-1
x(x^2+1) -1(x^2+1) - 1/x+1
x^3+x-x^2-1 - 1/x+1
x^3-x^2+x-1 - 1/x+1 ....
Answer:
Yes
Step-by-step explanation:
In right-angled triangles, the Theorem of Pythagoras can be applied. (The hypotenuse squared is equal to the sum of the other two sides squared).
The hypotenuse is always the longest side, therefore if it's a right-angled triangle:
15²+35² should equal to 38² and in this case it does.
let's firstly convert the mixed fraction to improper fraction, and divide, so we can see how many times 1/6 goes into 2⅔
![\bf \stackrel{mixed}{2\frac{2}{3}}\implies \cfrac{2\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{8}{3}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{8}{3}\div \cfrac{1}{6}\implies \cfrac{8}{3}\cdot \cfrac{6}{1}\implies \cfrac{8}{1}\cdot \cfrac{6}{3}\implies 8\cdot 2\implies 16](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B2%5Cfrac%7B2%7D%7B3%7D%7D%5Cimplies%20%5Ccfrac%7B2%5Ccdot%203%2B2%7D%7B3%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B8%7D%7B3%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B8%7D%7B3%7D%5Cdiv%20%5Ccfrac%7B1%7D%7B6%7D%5Cimplies%20%5Ccfrac%7B8%7D%7B3%7D%5Ccdot%20%5Ccfrac%7B6%7D%7B1%7D%5Cimplies%20%5Ccfrac%7B8%7D%7B1%7D%5Ccdot%20%5Ccfrac%7B6%7D%7B3%7D%5Cimplies%208%5Ccdot%202%5Cimplies%2016)
4x - 2y = 7....multiply by 3
3x + 6y = 9
-------------
12x - 6y = 21 (result of multiplying by 3)
3x + 6y = 9
-------------add
15x = 30
x = 30/15
x = 2
4x - 2y = 7
4(2) - 2y = 7
8 - 2y = 7
-2y = 7 - 8
-2y = -1
y = 1/2
solution (2,1/2)
