What phenotypes would you expect from a cross between a red bull and a white cow?

A 10-cm-long wire is pulled along a u-shaped conducting rail in a perpendicular magnetic field. the total resistance of the wire

Debora [2.8K]

In the above case we can say that power given by external agent to pull the rod must be equal to the power dissipated in the form of heat due to magnetic induction.

Part a)

when we pull the rod with constant speed then power required will be product of force and velocity

here we will have

$P = F.v$

P = 4 W

v = 4 m/s

now we will have

$4 = F*4$

$F = 1N$

So external force required will be 1 N

PART B)

now in order to find magnetic field strength we can say

$P = \frac{v^2B^2L^2}{R}$

here we know that induced EMF in the wire is E = vBL

so power due to induced magnetic field is given by

$P = \frac{E^2}{R}$

$4 = \frac{4^2*B^2*0.10^2}{0.20}$

by solving above equation we will have

$B = 2.24 T$

5 0

2 years ago

The energy of a photon is equal to (what) times (what) of the photon.

hjlf

The energy carried by a photon is equal to

(Planck's Konstant) times (the frequency of the photon) .

Planck's konstant is 6.626 x 10⁻³⁴ m²-kg/s (rounded)

3 0

2 years ago

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The red light from a helium-neon laser has a wavelength of 721.4 nm in air. Find the speed, wavelength, and frequency of helium-

saveliy_v [14]

Answer:

(a) the speed of helium-neon laser light in air is 3 x 10⁸ m/s

the wavelength of helium-neon laser light in air is 721.4 nm

the frequency of helium-neon laser light in air is 415.86 THz

(b) the speed of helium-neon laser light in water is 2.26 x 10⁸ m/s

the wavelength of helium-neon laser light in water is 542.4nm

the frequency of helium-neon laser light in water is 416.67THz

(c) the speed of helium-neon laser light in glass is 2 x 10⁸ m/s

the wavelength of helium-neon laser light in glass is 480.9nm

the frequency of helium-neon laser light in glass is 415.88THz

From the results above, it can be seen that speed of the light is directly proportional to its wavelength, while the frequency of the light remained fairly constant for the different media.

Explanation:

Part (a) the speed, wavelength, and frequency of helium-neon laser light in air

Given;

wavelength of helium-neon laser light in air, λ = 721.4 nm

speed of light in air, v = 3 x 10⁸ m/s

v = f λ

where;

f is the frequency of helium-neon laser light in air

$f = \frac{v}{\lambda} = \frac{3*10^8}{721.4 *10^{-9}} =4.1586*10^{14} \ Hz$

f = 415.86 THz

Part (b) the speed, wavelength, and frequency of helium-neon laser light in water

refractive index of water = 1.33

$Refractive \ index \ of \ water =\frac{speed \ of \ light \ in \ air}{speed \ of \ light \ in \ water} = \frac{wavelength \ of \ light \ in \ air}{wavelength \ of \ light \ in \ water}$

$speed \ of \ light \ in \ water = \frac{speed \ of \ light \ in \ air}{Refractive \ index \ of \ water} \\\\speed \ of \ light \ in \ water = \frac{3*10^8}{1.33} = 2.26 *10^8 \ m/s$

Again;

$wavelength \ of \ light \ in \ water = \frac{wavelength \ of \ light \ in \ air}{Refractive \ index \ of \ water} \\\\wavelength \ of \ light \ in \ water = \frac{721.4 \ nm}{1.33} = 542.4 \ nm$

$f = \frac{v}{\lambda} = \frac{2.26*10^8}{542.4 *10^{-9}} =4.1667*10^{14} \ Hz$

f = 416.67 THz

Part (c) the speed, wavelength, and frequency of helium-neon laser light in glass

Refractive index of glass = 1.5

$speed \ of \ light \ in \ glass = \frac{speed \ of \ light \ in \ air}{Refractive \ index \ of \ glass} \\\\speed \ of \ light \ in \ glass = \frac{3*10^8}{1.5} = 2 *10^8 \ m/s$

Also;

$wavelength \ of \ light \ in \ glass = \frac{wavelength \ of \ light \ in \ air}{Refractive \ index \ of \ glass} \\\\wavelength \ of \ light \ in \ glass = \frac{721.4 \ nm }{1.5} = 480.9 \ nm$

$f = \frac{v}{\lambda} = \frac{2*10^8}{480.9 *10^{-9}} =4.1588*10^{14} \ Hz$

f = 415.88 THz

5 0

2 years ago

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A wire that is 0.36 meters long moves perpendicularly through a magnetic field at a speed of 0.21 meters/second. The induced emf

dmitriy555 [2]

0.034 newtons/amp·meter

8 0

2 years ago

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Two balloons (m = 0.012 kg) are separated by a distance of d = 15 m. They are released from rest and observed to have an instant

Evgesh-ka [11]

Answer:

1.492*10^14 electrons

Explanation:

Since we know the mass of each balloon and the acceleration, let’s use the following equation to determine the total force of attraction for each balloon.

F = m * a = 0.012 * 1.9 = 0.0228 N

Gravitational forces are negligible

Charge force = 9 * 10^9 * q * q ÷ 225

= 9 * 10^9 * q^2 ÷ 225 = 0.0228

q^2 = 5.13 ÷ 9 * 10^9

q = 2.387 *10^-5

This is approximately 2.387 *10^-5 coulomb of charge. The charge of one electron is 1.6 * 10^-19 C

To determine the number of electrons, divide the charge by this number.

N =2.387 *10^-5 ÷ 1.6 * 10^-19 = 1.492*10^14 electrons

3 0

2 years ago