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2 years ago

Hurry i only have till today to finsh this!

Chemistry

2 answers:

Leona [35]2 years ago

5 0

Answer:

do it yourself

Explanation:

AfilCa [17]2 years ago

4 0

Answer:

With the friction on, the minimum height I can place the skater so that he makes it all the way around the loop is 6 meters. This is about a meter higher than if the friction were turned off. The “lost” energy is going towards thermal energy. This means in real life that heat is being created due to the friction.

Explanation:

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Iron and vanadium both have the BCC crystal structure and V forms a substitutional solid solution for concentrations up to appro

Hatshy [7]

Answer:

The unit cell edge length for the alloy is 0.288 nm

Explanation:

Given;

concentration of vanadium, Cv = 8 wt%

concentration of iron, Cfe = 92 wt%

density of vanadium = 6.11 g/cm³

density of iron = 7.86 g/cm³

atomic weight of vanadium, Av = 50.94 g/mol

atomic weight of iron, Afe= 55.85 g/mol

Step 1: determine the average density of the alloy

$\rho _{Avg.} = \frac{100}{\frac{C_v}{\rho _v} + \frac{C__{Fe}}{\rho _{Fe}} }$

$\rho _{Avg.} = \frac{100}{\frac{8}{6.11} + \frac{92}{7.86} } = 7.68 \ g/cm^3$

Step 2: determine the average atomic weight of the alloy

$A _{Avg.} = \frac{100}{\frac{C_v}{A _v} + \frac{C__{Fe}}{A _{Fe}} }$

$A _{Avg.} = \frac{100}{\frac{8}{50.94} + \frac{92}{55.85} } = 55.42 \ g/mole$

Step 3: determine unit cell volume

$V_c=\frac{nA_{avg.}}{\rho _{avg.} N_a}$

for a BCC crystal structure, there are 2 atoms per unit cell; n = 2

$V_c=\frac{2*55.42}{ 7.68*6.022*10^{23}} = 2.397*10^{-23} \ cm^3/cell$

Step 4: determine the unit cell edge length

Vc = a³

$a = V_c{^\frac{1}{3} }\\\\a = (2.397*10^{-23}}){^\frac{1}{3}}\\\\a = 2.88 *10^{-8} \ cm$ = 0.288 nm

Therefore, the unit cell edge length for the alloy is 0.288 nm

4 0

3 years ago

What is the relationship between a codon and an anticodon?

alexgriva [62]

They both share oxygen

6 0

2 years ago

If the only chemical you can find is labeled with the wrong concentration:_______

Softa [21]

Answer:inform the lab instructor and get instructions

Explanation:

If you come across a chemical in the laboratory which has been wrongly labelled, do not be quick to dilute it or take any further action. The laboratory instructor who may have prepared the reagent himself or has better knowledge about the reagent should be contacted immediately so that he/she can give you instructions about what to do with the wrongly labelled reagent.

3 0

2 years ago

R.I.P too my brainly account lol..

Vera_Pavlovna [14]

Answer:

i don't know what happened but r.i.p account

3 0

2 years ago

Read 2 more answers

A pulse with an amplitude of 3+ would be considered:

alexdok [17]

<span>A pulse with an amplitude of 3+ would be considered as increased. Peripheral Pulse Assessment Grading System is measured in 0 - 3 Scale. 0 = absent 1+ = Weak/thready pulse 2+ Normal Pulse 3+ = Full, firm pulse. from the above scale we can find that the 3+ reading shows that the pulse is increased.</span>

4 0

2 years ago