Find the distance UV between the points U(4,−2) and V(6,−1). Round your answer to the nearest tenth, if necessary.

Mathematics

1 answer:

Liono4ka [1.6K]2 years ago

8 0

The horizontal distance is the difference of x-coordinates: 6 - 4 = 2.

The vertical distance is the difference of y-coordinates: -1 - (-2) = 1.

The straight-line distance (d) can be found using the Pythagorean theorem, since the vertical and horizontal distances are at right angles to each other.

.. d² = 2² + 1² = 5

.. d = √5 ≈ 2.2

The distance UV is about 2.2.

You might be interested in

Suppose you are solving an inequality. Under what circumstances do you reverse the inequality symbol? Select all that apply.

eduard

The answer is C! Hope this helps :)

3 0

2 years ago

Read 2 more answers

How May I Draw My number Line And Where Would My Numbers Go?

Digiron [165]

.5 is basically 1/2. We know this because .5 written as a fraction is 50/100 which you can simplify to 1/2.

6/10 is greater than 1/2. You can find this out by converting 1/2 to tenths. Multiply the numerator and the denominator by 5 to get 5/10. From there you can easily see that 6/10 > 5/10.

As for the number line simply use 10ths: 1/10, 2/10, 3/10 ... and input 6/10 and 5/10 in the appropriate areas.

4 0

2 years ago

What's the difference between 6z and z6

Airida [17]

Simple..

there is a major difference between 6z and $z^{6}$

6z means: 6 times z

and

$z^{6}$ means: z to the power of 6(z*z*z*z*z*z)

An example...

make z=2...plug n chug..

6z----> 6(2)=12
and
$z^{6}$ ---> $2^{6}$ =64

As you can see..there is a major difference.

Thus, your answer.

4 0

2 years ago

10 Pts Multiplying fractions: 5 1 — x — = 6 2

Flauer [41]

Multiply the numerators together. Multiply the denominators together. Then reduce if necessary.

$\dfrac{first~numerator}{first~denominator} \times \dfrac{second~numerator}{second~denominator} = \dfrac{(first~numerator)\times(second~numerator)}{(first~denominator)\times(second~denominator)}$