1 pound = 16 ounces
So we have 85 lbs and 2 oz, that is if we convert them to ounces:
85(16) + 2 = 1362 oz
so we have 1362 oz total due to the conversion factor stated above, now we only need to divide:
1362/6 = 227
that is 227 oz
or if we want the result in pounds (lbs), we can by dividing again by 16
227/16 = 14.19 lbs
A of the yard= L*l=16*14= 224 feet²
A of the fountain= πR²
d=2R
4=2R
R=4:2=2
A of the fountain= 2²π=4 *3,14= 12,56 feet²
A of the grass portion= 224-12,56= 211,43 feet²
answer d)211,43 feet²
Answer:
$51.70 is the original price
Step-by-step explanation:
Step 1:
Turn 40% into a decimal which makes it 0.40
ex. 50% would be 0.50, 5% would be 0.05 etc.
Step 2:
Put the numbers into this formula: Original Price (x) - Percent Off times Original Price = Sales Price
x - 0.40x = 31.02 this is basically 1x - 0.40x = 31.02 so,
Solving the left side of our equation gives us 1x - 0.40x = 0.60x
so now you have: 0.60x = 31.02
Step 3:
Divide both sides by 0.60 which gets x by itself and gives us the original price which is $51.70
Answer:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Step-by-step explanation:
For this case first we need to create the sample of size 20 for the following distribution:
And we can use the following code: rnorm(20,50,6) and we got this output:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Answer:
360 square inches
Step-by-step explanation:
12*15 = 360