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2 years ago

Write in point-slope form an equation of the line that passes through the given point and has the given slope.

Mathematics

1 answer:

andre [41]2 years ago

5 0

The point-slope form:

$y-y_1=m(x-x_1)$

3. (4, -2); m = 1/4

$y-(-2)=\dfrac{1}{4}(x-4)\\\\\boxed{y+2=\dfrac{1}{4}(x-4)}$

4. (-3, 5); m = -4/3

$y-5=-\dfrac{4}{3}(x-(-3))\\\\\boxed{y-5=-\dfrac{4}{3}(x+3)}$

5. (2, 2); m= - 1

$\boxed{y-2-(x-2)}$

6. (-1, -5); m = 4

$y-(-5)=4(x-(-1))\\\\\boxed{y+5=4(x+1)}$

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The price p based on the equation given is p = 3000 - 0.1x.

<h3>How to express the price?</h3>

The equation given in the question is x = 3000 - 10p. The price(p) will be:

x = 3000 - 10p.

Make p the subject of the formula

x + 10p = 3000

10p = 3000 - x

p = (3000 - x)/10

p = 3000 - 0.1x

The revenue will be price multiplied by quantity. This will be:

= (3000 - 0.1x) × x

= 3000x - 0.1x²

The marginal revenue will be calculated after differentiating. This will be:

= 3000x - 0.1x²

= 3000 - 0.2x

The demand which is the quantity based on the information will be:

3000 - 0.2x = 0

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Graph y - 2 = -3/4 (x - 6) using the point and slope given in the equation.

Dafna1 [17]

Answer:

Step-by-step explanation:

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3 years ago

Jocelynn paid $3.01 for an item which cost $34.80 before sales tax is applied. If the sales tax remains the same, how much money

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2 years ago

HELPP!!!!!!!!!!!!!!!!

Anvisha [2.4K]

Answer:

Step-by-step explanation:

We'll take this step by step. The equation is

$8-3\sqrt[5]{x^3}=-7$

Looks like a hard mess to solve but it's actually quite simple, just do one thing at a time. First thing is to subtract 8 from both sides:

$-3\sqrt[5]{x^3}=-15$

The goal is to isolate the term with the x in it, so that means that the -3 has to go. Divide it away on both sides:

$\sqrt[5]{x^3}=5$

Let's rewrite that radical into exponential form:

$x^{\frac{3}{5}}=5$

If we are going to solve for x, we need to multiply both sides by the reciprocal of the power:

$(x^{\frac{3}{5}})^{\frac{5}{3}}=5^{\frac{5}{3}}$

On the left, multiplying the rational exponent by its reciprocal gets rid of the power completely. On the right, let's rewrite that back in radical form to solve it easier:

$x=\sqrt[3]{5^5}$

Let's group that radicad into groups of 3's now to make the simplifying easier:

$x=\sqrt[3]{5^3*5^2}$ because the cubed root of 5 cubed is just 5, so we can pull it out, leaving us with:

$x=5\sqrt[3]{5^2}$ which is the same as:

$x=5\sqrt[3]{25}$

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2 years ago