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2 answers:
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Answer:
B. No, this distribution does not appear to be normal
Step-by-step explanation:
Hello!
To observe what shape the data takes, it is best to make a graph. For me, the best type of graph is a histogram.
The first step to take is to calculate the classmark`for each of the given temperature intervals. Each class mark will be the midpoint of each bar.
As you can see in the graphic (2nd attachment) there are no values of frequency for the interval [40-44] and the rest of the data show asymmetry skewed to the left. Just because one of the intervals doesn't have an observed frequency is enough to say that these values do not meet the requirements to have a normal distribution.
The answer is B.
I hope it helps!
Answer:
So then the difference between the two proportions is 0.045 and if we convert this into % we got
Step-by-step explanation:
For this case we can define the following notation:
represent the unemployment rate for high school graduates with no college degree
represent the unemployment rate for college graduates with a bachelor's degree
And for this case we need to find the difference in proportions of those unemployed between these two groups, we want to find:
From the info given we have
And the difference:
So then the difference between the two proportions is 0.045 and if we convert this into % we got