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2 years ago

Can you please help with this math?>>

Mathematics

2 answers:

goblinko [34]2 years ago

6 0

x = 16 x sin(60) = 8sqrt(3)

answer is B.

lana66690 [7]2 years ago

6 0

16 is your hypotenuse, (2)
The top length is your (1)
The x is your (√3)

To find x, first find your side 1, by dividing the side "2" number by half
16/2 = 8

Than place the 8 with the √3

8√3 is your answer

hope this helps

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Which of the following options have the same value as 30\%30%30, percent of 818181?

Nataly_w [17]

Answer:

Option B is correct = $0.3 \times 81$

Step-by-step explanation:

The complete question is: Which of the following options have the same value as 30% of 81?

Group of choices is:

(A) $\frac{30}{100}\times 81 \times 100$

(B) $0.3 \times 81$

(D) $\frac{3}{10}\times 81 \times 10$

(E) $30 \times 81$

Now, the expression given to us is 30% of 81.

Simplifying the above expression we get;

30% of 81 = $\frac{30}{100} \times 81$

= $\frac{3}{10} \times 81$ = $0.3 \times 81$

Now, we will solve each of the given options and then see which option matches with our calculation.

Option (A) is given;

$\frac{30}{100}\times 81 \times 100$ = $30 \times 81$

This doesn't match with our answer, so this option is not correct.

Option (B) is given;

$0.3 \times 81$

This matches with our answer, so this option is correct.

Option (C) is given;

$0.03 \times 81$

This doesn't match with our answer, so this option is not correct.

Option (D) is given;

$\frac{3}{10}\times 81 \times 10$ = $3 \times 81$

This doesn't match with our answer, so this option is not correct.

Option (E) is given;

$30 \times 81$

This doesn't match with our answer, so this option is not correct.

6 0

3 years ago

p borrowed Rs. 16000 from a person at 12 % per Annum simple interest and lent the whole amount to Q at the same rate of annually

hichkok12 [17]

Answer:

P earned $ 718.85.

Step-by-step explanation:

Given that P borrowed $ 16000 from a person at 12% per annum simple interest and lent the whole amount to Q at the same rate of annually compound interest, to determine how much did he gain after 3 years the following calculation must be performed:

16,000 x 0.12 x 3 = X

1,920 x 3 = X

5,760 = X

16,000 x (1 + 0.12 / 1) ^ 3 = X

16,000 x 1.12 ^ 3 = X

16,000 x 1.404928 = X

22,478.85 = X

22,478.85 - 16,000 = 6,478.85

6,478.85 - 5,760 = X

718.85 = X

Therefore, P earned $ 718.85.

5 0

2 years ago

What is the greatest common factor of 34 and 58

Stella [2.4K]

The greatest common factor is 2

8 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=5%28sin%28t%29%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%2Bycos%28t%29%29%29%3Dcos%28t%29%20%20%28sin%28

Nataliya [291]

Assuming you mean

$5\sin t\dfrac{\mathrm dy}{\mathrm dt}+5y\cos t=\cos t\sin^2t$

This ODE is linear in $y$ , and you can already contract the left hand side as the derivative of a product:

$\dfrac{\mathrm d}{\mathrm dt}\left[5y\sin t\right]=\cos t\sin^2t$

Integrating both sides with respect to $t$ yields

$5y\sin t=\displaystyle\int\cos t\sin^2t\,\mathrm dt$
$5y\sin t=\dfrac13\sin^3t+C$
$y=\dfrac1{15}\sin^2t+C\csc t$

Given that $y\left(\dfrac\pi2\right)=9$ , we have

$9=\dfrac1{15}\sin^2\dfrac\pi2+C\csc\dfrac\pi2$
$9=\dfrac1{15}+C$
$C=\dfrac{134}{15}$

so that the particular solution over the interval is

$y=\dfrac1{15}\sin^2t+\dfrac{134}{15}\csc t$

6 0

2 years ago

a set of data has the following linear regression equation y = 1+3x what does the equation predict for a value of x=14?

trasher [3.6K]

In this problem, you are simply going to input 14 for x in your equation.

y = 3x + 1
y = 3(14) + 1
y = 42+1
y = 43
This means, when x=14, y=43

Hope this helps!

6 0

2 years ago