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2 years ago

10

How to write 0.99966788 in scientific notation?

2 answers:

inn [45]2 years ago

7 0

Answer:

9.9966788 x 10^-1

mars1129 [50]2 years ago

4 0

Move the decimal 4 times to the right than thay number tomes 10^-4

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HELP!! - <br><br> Very appreciated! :)

IgorLugansk [536]

Your answer is 2 goes to the right and twice to the left

6 0

2 years ago

Which describes the dissolving process? (Choose all that Apply)

stich3 [128]

Answer:

A and D

Explanation:

I took the test, and choose both B and C and got it wrong

4 0

2 years ago

Acetaminophen is the generic name of the pain reliever in Tylenol and some other headache remedies- The compoundhas the molecula

slega [8]

<u>Answer:</u> The mass percentage of carbon element is 63.57 %, hydrogen element is 5.96 %, nitrogen element is 9.28 % and oxygen element is 21.19 %

<u>Explanation:</u>

We are given:

A chemical compound having chemical formula of $C_8H_9NO_2$ . This compound is made by the combination of carbon, hydrogen, nitrogen and oxygen elements.

1 mole of acetaminophen contains 8 moles of carbon atom, 9 moles of hydrogen atom, 1 mole of nitrogen atom and 2 moles of oxygen atom

Mass of carbon element = $(8\times 12)=96g/mol$

Mass of hydrogen element = $(9\times 1)=9g/mol$

Mass of nitrogen element = $(1\times 14)=14g/mol$

Mass of oxygen element = $(2\times 16)=32g/mol$

Mass of the compound = 151 g/mol

To calculate the percentage composition of an element in a compound, we use the equation:

$\%\text{ composition of an element}=\frac{\text{Mass of element}}{\text{Mass of compound}}\times 100$ ........(1)

<u>For carbon element:</u>

Putting values in equation 1, we get:

$\% \text{ composition of carbon element}=\frac{96}{151}\times 100\\\\\% \text{ composition of carbon element}=63.57\%$

<u>For hydrogen element:</u>

Putting values in equation 1, we get:

$\% \text{ composition of hydrogen element}=\frac{9}{151}\times 100\\\\\% \text{ composition of hydrogen element}=5.96\%$

<u>For nitrogen element:</u>

Putting values in equation 1, we get:

$\% \text{ composition of nitrogen element}=\frac{14}{151}\times 100\\\\\% \text{ composition of nitrogen element}=9.28\%$

<u>For oxygen element:</u>

Putting values in equation 1, we get:

$\% \text{ composition of oxygen element}=\frac{32}{151}\times 100\\\\\% \text{ composition of oxygen element}=21.19\%$

Hence, the mass percentage of carbon element is 63.57 %, hydrogen element is 5.96 %, nitrogen element is 9.28 % and oxygen element is 21.19 %

6 0

2 years ago

A 0.175 M solution of an enantiomerically pure chiral compound D has an observed rotation of +0.27° in a 1-dm sample

-BARSIC- [3]

Answer:

The specific rotation of D is 11.60° mL/g dm

Explanation:

Given that:

The path length (l) = 1 dm

Observed rotation (∝) = + 0.27°

Molarity = 0.175 M

Molar mass = 133.0 g/mol

Concentration in (g/mL) = 0.175 mol/L × 133.0 g/mol

Concentration in (g/mL) = 23.275 g/L

Since 1 L = 1000 mL

Concentration in (g/mL) = 0.023275 g/mL

The specific rotation [∝] = ∝/(1×c)

= 0.27°/( 1 dm × 0.023275 g/mL )

= 11.60° mL/g dm

Thus, the specific rotation of D is 11.60° mL/g dm

3 0

2 years ago

What is the noble gas electron configuration of bismuth (Bi)? A. [Kr] 6s2 6p3 B. [Xe] 6s2 6p3 C. [Xe] 4f14 5d10 6s2 6p3 D. [Kr]

OlgaM077 [116]

The answer is C) Xe 4f14 5d10 6s2 6p3

4 0

2 years ago

Read 2 more answers