1 year ago

Please help I would be very grateful

1 answer:

6 0

Let’s see um so first you..

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anzhelika [568]

Answer: {(5,0), (3,4)}

Step-by-step explanation:

You can apply the Substitution method:

- Solve for y from the second equation.

- Substitute into the first equation and solve for x.

Then:

$y=10-2x$

$x^2+y^2=25\\x^2+(10-2x)^2=25\\$

(Remember that: $(a\±b)^2=a^2\±2ab+b^2$ )

$x^2+(10^2-2(10)(2x)+(2x)^2)=25\\x^2+100-40x+4x^2=25\\5x^2-40x+75=0\\x^2-8x+15=0\\(x-5)(x-3)=0\\\\x=5\\x=3$

Substitute the values obtained into one of the original equation and solve for y:

$2(5)+y=10\\10+y=10\\y=0\\\\2(3)+y=10\\6+y=10\\y=4$

The solution set is: {(5,0), (3,4)}

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2 years ago