I observed that if I remove one (or all 8) piece(s) in the corners, and only them without adjacent ones, the total area does not change.
I consider the surface area of a small square as a unit of surface.
First class of solutions:
I removed all eight corners, leaving the total area unchanged.
I removed the central cube of the top surface obtaining an increase of the surface area with four units.
I removed one cube from the middle of an edge at the top (any of the four remaining) and I arrived at a figure with ten cubes less then the original one but with the same surface area.
(There's a lot more solutions here: https://nrich.maths.org/787/solution)
Answer:
23 in
Step-by-step explanation:
Volume of a Cube: V = a³
Step 1: Define
V = 12,167 in³
a = ?
Step 2: Solve for side length <em>a</em>
- <u>Substitute:</u> 12,167 = a³
- <u>Cube root both sides:</u> 23 = a
- <u>Rewrite:</u> a = 23
Step 3: Check
<em>Plug in a to verify it's a solution.</em>
- <u>Substitute: </u>V = (23 in)³
- <u>Evaluate:</u> V = 12,167 in³
The unknown digit is 7 because 6.471 is greater than 6.470 and less than 6.48.
Answer:
92000
Step-by-step explanation:
2119 is less then 500
Answer:
56.52mm
Step-by-step explanation:
