Answer:
At (-2,0) gradient is -4 ; At (2,0) gradient is 4
Step-by-step explanation:
For this problem, we simply need to take the derivative of the function and evaluate when y = 0 (when crossing the x-axis).
y = x^2 - 4
y' = 2x
The function y = x^2 - 4 cross the x-axis when:
y = x^2 - 4
0 = x^2 - 4
4 = x^2
2 +/- = x
Hence, this curve crosses the x-axis twice, once at (-2,0) and again at (2,0).
The gradient at these points are as follows:
y' = 2(-2) = -4
y' = 2(2) = 4
Cheers.
Answer:
5.85 m
Step-by-step explanation:
The width of the sand road can be calculated knowing its area and the dimensions of the rectangular garden as follows:
<u>Where:</u>
Ag: is the area of the rectangular garden
a: is the length of the rectangular garden = 50 cm = 0.5 m
b: is the width of the rectangular garden = 34 m
<u>Where</u>:
As: is the area of the sand road
The relation between the area of the sand road and the area of the rectangular garden is the following:
By solving the above equation for x we have two solutions:
x₁ = -23.10 m
x₂ = 5.85 m
Taking the positive value, we have that the width of the sand road is 5.85 m.
I hope it helps you!
Let the lesser number be x and y the greater. Then
x + 65 = 4y , Also
y - x = 2
Adding:-
y + 65 = 4y + 2
63 = 3y
y = 21
and
x = 21-2 = 19
Answer the 2 odd numbers are 19 and 21.
Answer: 1.76
1.54
Step-by-step explanation:
we have to divide 800 by 453.592, and the result is 1.763699... rounding it: 1.76
now we do the same for 700 :
700 divided by 453.592 is 1.5432... so rounding it down: 1.54
Trig ratios can only be used on right triangles with acute measures.
If given an angle and there are adjacent and opposite sides, then use tan(opposite/adjacent)
If given an angle and there is an adjacent side and a hypotenuse, then use cosine(adjacent/hypotenuse)
If given an angle and there is an opposite and adjacent side, then use sin(opposite/hypotenuse)
A common mnemonic device used to memorize the trig rules is SOH-CAH-TOA