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1 year ago

10

Sheza and Hadia had 12579 paper stars. Sheza gave 2214 paper stars to Hadia. Now Hadia had twice as many paper stars as Sheza. H

ow many paper stars did Hadia had at first?

1 answer:

makvit [3.9K]1 year ago

7 0

Answer:

10365

Step-by-step explanation:

12579 - 2214

= 10365

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Convert to an improper fraction. Type in your answer with the negative in the numerator.

MariettaO [177]

Answer:

-35/4

Step-by-step explanation:

6 0

2 years ago

In the square below, the two semi-circles are congruent. Find the area of the shaded region. If necessary, round your answer to

Jobisdone [24]

Let's start with the area of the square
$area \: square = s \times s = 8 \times 8 = 64$
now let's subtract the are of the two half circles.
two half circles are the same as one circle, and we know that the diameter of the circle is 8 (same as the side of a square) so it's radius is 8/2= 4 inches

$area \: circle = \pi {r}^{2} = \pi \times {4}^{2} = 16\pi$
now we just subtract and our answer is

$64 - 16\pi = 64 - 16 \times (3.14) = 13.73$

3 0

2 years ago

Which is a factor of the polynomial f(x) = 6x4 – 21x3 – 4x2 + 24x – 35?

QveST [7]

<span>I note that this problem starts out with "Which is a factor of ... " This implies that you were given several answer choices. If that's the case, it's unfortunate that you haven't shared them.

I thought I'd try finding roots of this function using synthetic division. See below:

f(x) = 6x^4 – 21x^3 – 4x^2 + 24x – 35
Please use " ^ " to denote exponentiation. Thanks.

Possible zeros of this poly are factors of 35: plus or minus 1, plus or minus 5, plus or minus 7. Use synthetic division; determine whether or not there is a non-zero remainder in each case. If none of these work, form rational divisors from 35 and 6 and try them: 5/6, 7/6, 1/6, etc.

Provided that you have copied down the function
</span>f(x) = 6x^4 – 21x^3 – 4x^2 + 24x – 35 properly, this approach will eventually turn up 1 or 2 zeros of this poly. Obviously it'd be much easier if you'd check out the possible answers given you with this problem.

By graphing this function, I found that the graph crosses the x-axis at 7/2. There is another root.

Using synth. div. to check whether or not 7/2 is a root:

___________________________
7/2 / 6 -21 -4 24 -35
21 0 -14 35
----------- ------------------------------
6 0 -4 10 0

Because the remainder is zero, 7/2 (or 3.5) is a root of the polynomial. Thus, (x-3.5), or (x-7/2), is a factor.

7 0

2 years ago

Read 2 more answers

Quadrilateral EFGH has the vertices E (-1,5), F (-2,3), G (-9,7), H (-3,6). What quadrant would all the vertices of quadrilatera

LenaWriter [7]

Answer:

Quadrant III

Step-by-step explanation:

5 0

2 years ago

For the years from 2002 and projected to 2024, the national health care expenditures H, in billions of dollars, can be modeled b

dmitriy555 [2]

Answer:

2019.

Step-by-step explanation:

We have been given that for the years from 2002 and projected to 2024, the national health care expenditures H, in billions of dollars, can be modeled by $H = 1,500e^{0.053t}$ where t is the number of years past 2000.

To find the year in which national health care expenditures expected to reach $4.0 trillion (that is, $4,000 billion), we will substitute $H=4,000$ in our given formula and solve for t as:

$4,000= 1,500e^{0.053t}$

$\frac{4,000}{1,500}=\frac{ 1,500e^{0.053t}}{1,500}$

$\frac{8}{3}=e^{0.053t}$

$e^{0.053t}=\frac{8}{3}$

Take natural log of both sides:

$\text{ln}(e^{0.053t})=\text{ln}(\frac{8}{3})$

$0.053t\cdot \text{ln}(e)=\text{ln}(\frac{8}{3})$

$0.053t\cdot (1)=0.9808292530117262$

$\frac{0.053t}{0.053}=\frac{0.9808292530117262}{0.053}$

$t=18.506212320$

So in the 18.5 years after 2000 the expenditure will reach 4 trillion.

$2000+18.5=2018.5$

Therefore, in year 2019 national health care expenditures are expected to reach $4.0 trillion.

7 0

3 years ago