No it far 10 is way out there
-16w-26+9w=-61
-16w+9w=-61+26
-7w=-35
w=5
Answer:
Step-by-step explanation:
Average Temperatures Suppose the temperature (degrees F) in a river at a point x meters downstream from a factory that is discharging hot water into the river is given by
T(x) = 160-0.05x^2
a. [0, 10]
For x = 0
T(0) = 160 - 0.05 × 0^2
T(0) = 160
For x = 10
T(10) = 160 - 0.05 × 10^2
T(10) = 160 - 5 = 155
The average temperature
= (160 + 155)/2 = 157.5
b. [10, 40]
For x = 10
T(10) = 160 - 0.05 × 10^2
T(10) = 160 - 5 = 155
For x = 40
T(10) = 160 - 0.05 × 40^2
T(10) = 160 - 80 = 80
The average temperature
= (80 + 155)/2 = 117.5
c. [0, 40]
For x = 0
T(0) = 160 - 0.05 × 0^2
T(0) = 160
For x = 40
T(10) = 160 - 0.05 × 40^2
T(10) = 160 - 80 = 80
The average temperature
= (160 + 80)/2 = 120
Subtract what has already been loaded from total amount allowed:
23500 - 9700 = 13,800
Divide the amount left by the weight of each crate:
13,800 / 70 = 197.14
They can load 197 crates.
Answer:
C (37, 77)
Step-by-step explanation:
<h3>Option A:</h3>
Option A is not a solution.
<h3>Option B:</h3>
Option B is not a solution.
<h3>Option C:</h3>
Option C is a solution.
Hope this helps.