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1 year ago

Please help me solve this problems

Mathematics

2 answers:

Mama L [17]1 year ago

6 0

Answer:

35 degrees.

Step-by-step explanation:

Since that the line that the exterior 100 degree angle is on is a straight line (which is 180 degrees) we can clearly see the supplementary angle is 180-100 which is 80. A triangle's interior angles add up to 180 degrees which means the missing angle is 180-80-6535 degrees.

bagirrra123 [75]1 year ago

3 0

Answer:

m angle FED is 35 degrees

Step-by-step explanation:

line DE is bisecting RF.

linear lines have a 180 degree angle.

you are given that m angle RDE is 100, meaning you can subtract 180-100 to find angle FDE.

angle FDE is 80 degrees.

in EVERY triangle, all of the angles always add up to 180 degrees. Knowing this, you can subtract 80 and 65 from 180 to find the missing angle.

180 - 80 - 65 = 35

m angle FED is 35 degrees

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2 years ago

Kyle incorrectly says that the product of - ( - 6 ) # ( - 1 ) is 6 . 11. After a recycling awareness program, the number of tons

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Complete question:

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Answer:

Kindly check explanation

Step-by-step explanation:

Given that :

Kyle incorrectly says that the product of - ( - 6 ) ( - 1 ) is 6

-(-6)(-1) = 6 [incorrect]

Correction:

-(-6) (-1) :

- (-6) = 6

6 (-1) = - 6

Given that reduction in materials = 13 7/10 tons per month

Monthly reduction = 13 7/10 = 137/10 tons

After 7 months : (7 * 137/10) = 959/10 tons = 95.9 tons

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Initial amount - amount after 7 months

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2 years ago

Find the missing side<br> 1) 6<br> 2) 6.41<br> 3)6.40

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Answer:

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Explanation:

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1 year ago

Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
$(x+2)^2+(y-3)^2=18$
$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
$(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2$

the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
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$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
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do r<D

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