1.35 divided by 3.8 repeating

Mindy and Troy combined ate 999 pieces of the wedding cake. Mindy ate 333 pieces of cake and Troy had 1/4 of the total cake. W

lubasha [3.4K]

Answer:

Step-by-step explanation:

333+p/4=999

p/4=666

p=2664

6 0

2 years ago

Read 2 more answers

HELP FAST ALL OF MY POINTS TO BE GIVEN TO YOU

gogolik [260]

Answer:

C > 9

Step-by-step explanation:

3 0

2 years ago

Suppose that each observation in a random sample of 100 fatal bicycle accidents in 2015 was classified according to the day of t

liraira [26]

Answer:

The calculated χ² = 0.57 does not fall in the critical region χ² ≥ 12.59 so we fail to reject the null hypothesis and conclude the proportion of fatal bicycle accidents in 2015 was the same for all days of the week.

Step-by-step explanation:

1) We set up our null and alternative hypothesis as

H0: proportion of fatal bicycle accidents in 2015 was the same for all days of the week

against the claim

Ha: proportion of fatal bicycle accidents in 2015 was not the same for all days of the week

2) the significance level alpha is set at 0.05

3) the test statistic under H0 is

χ²= ∑ (ni - npi)²/ npi

which has an approximate chi square distribution with ( n-1)=7-1= 6 d.f

4) The critical region is χ² ≥ χ² (0.05)6 = 12.59

5) Calculations:

χ²= ∑ (16- 14.28)²/14.28 + (12- 14.28)²/14.28 + (12- 14.28)²/14.28 + (13- 14.28)²/14.28 + (14- 14.28)²/14.28 + (15- 14.28)²/14.28 + (18- 14.28)²/14.28

χ²= 1/14.28 [ 2.938+ 5.1984 +5.1984+1.6384+0.0784 +1.6384+13.84]

χ²= 1/14.28[8.1364]

χ²= 0.569= 0.57

6) Conclusion:

The calculated χ² = 0.57 does not fall in the critical region χ² ≥ 12.59 so we fail to reject the null hypothesis and conclude the proportion of fatal bicycle accidents in 2015 was the same for all days of the week.

b. It is reasonable to conclude that the proportion of fatal bicycle accidents in 2015 was the same for all days of the week

6 0

2 years ago

Show that (0, 0) is equidistant from (1, 2), (-1, -2) and (2, 1).

Len [333]

Step-by-step explanation:

1) if (0;0) if point A, (1;2) is point B; (-1;-2) is C, (2;1) is D, then

2) the vector AB is (1;2); vector AC is (-1;-2) and vector AD is (2;1), then

3) the length of AB, AC and AD are:

$|AB|=\sqrt{1^2+2^2}=\sqrt{5};$

$|AC|=\sqrt{(-1)^2+(-2)^2}=\sqrt{5};$

$|AD|=\sqrt{2^2+1^2}=\sqrt{5}.$

4) if the lengths above are equal, then it means that (0, 0) is equidistant from (1, 2), (-1, -2) and (2, 1).

3 0

1 year ago

Find the length of UT.

otez555 [7]

Answer: A. 32

Concept:

Here, we need to know the idea of the intersecting chord theorem and segment addition postulate.

The intersecting chord theorem states that when two chords intersect at a point, P, the product of their respective partial segments is equal.

The Segment Addition Postulate states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.

If you are still confused, please refer to the attachment below for a graphical explanation.

Solve:

Given information

CW = 12

TW = 14

VW = 2x + 5

UW = 2x + 2

Given expression deducted from intersecting chord theorem

CW · VW = TW · UW

Substitute values into the expression

(12) · (2x + 5) = (14) · (2x + 2)

Expand parentheses and apply the distributive property

24x + 60 = 28x + 28

Subtract 14x on both sides

24x + 60 - 24x = 28x + 28 - 24x

60 = 4x + 28

Subtract 28 on both sides

60 - 28 = 4x + 28 - 28

32 = 4x

Divide 4 on both sides

32 / 4 = 4x / 4

x = 8

Given expression deducted from the segment addition postulate

UT = UW + TW

Substitute values into the expression

UT = 2x + 2 + 14

Substitute x value into the expression

UT = 2 (8) + 2 + 14

UT = 16 + 2 + 14

Combine like terms

UT = 32

Hope this helps!! :)

Please let me know if you have any questions

5 0

1 year ago