Answer:
The dimensions of the yard are W=20ft and L=40ft.
Step-by-step explanation:
Let be:
W: width of the yard.
L:length.
Now, we can write the equation of that relates length and width:
(Equation #1)
The area of the yard can be expressed as (using equation #1 into #2):
(Equation #2)
Since the Area of the yard is , then equation #2 turns into:
Now, we rearrange this equation:
We can divide the equation by 5 :
We need to find the solution for this quadratic. Let's find the factors of 160 that multiplied yields -160 and added yields -12. Let's choose -20 and 8, since and . The equation factorised looks like this:
Therefore the possible solutions are W=20 and W=-8. We discard W=-8 since width must be a positive number. To find the length, we substitute the value of W in equation #1:
Therefore, the dimensions of the yard are W=20ft and L=40ft.
The answer to your question is 3k^2m^6/4
Answer:
-9/7
Step-by-step explanation:
Put the equation into y = mx + b form, by first isolating y:
9x + 7y= 7
7y = -9x + 7
Divide each side by 7:
y = -9/7x + 1
So, -9/7 is the slope.
<span>The square root of (a * b) is equal to (the square root of a) * (the square root of b)
-32 equals 32 * -1; therefore, the square root of -32 equals the square root of 32 times the square root of -1.
32 equals 16 * 2; the square root of 32 equals ? 16 * ?2 equals 4* ?2
The square root of -1 is i.
Therefore (2? -32) equals 2 * 4 * i * ?2 = 8i?2</span>