In this case we know the three sides of the triangle, then this is a SSS triangle (Side Side Side). To solve this case, first we must use the Law of Cosines, applied to the opposite side to the angle we want to find.
We want to find angle W, and its opposite side is XV, then we apply the Law of Cosines to the side XV:
XV^2=XW^2+WV^2-2(XW)(WV)cos W
Replacing the known values:
116^2=96^2+89^2-2(96)(89)cos W
Solving for W
13,456=9,216+7,921-17,088 cos W
13,456=17,137-17,088 cos W
13,456-17,137=17,137-17,088 cos W-17,137
-3,681=-17,088 cos W
(-3,681)/(-17,088)=(-17,088 cos W)/(-17,088)
0.215414326=cos W
cos W = 0.215414326
Solving for W:
W= cos^(-1) 0.215414326
Using the calculator:
W=77.56016397°
Rounded to one decimal place:
W=77.6°
Answer: Third option 77.6°
Answer:
m < amc = 54°
Step-by-step explanation:
< amb and < bmc are complementary angles whose sum equals 90°.
Therefore, to find the value of 2x°, we must first solve for x.
We can establish the following equality statement:
< amb + < bmc = < amc
< 2x° + (x + 9)° = 90°
Combine like terms:
2x° + x° + 9° = 90°
3x° + 9° = 90°
Subtract 9 from both sides:
3x° + 9° - 9° = 90° - 9°
3x = 81°
Divide both sides by 3 to solve for x:
3x/3 = 81°/3
x = 27°.
Since x = 27°, substitute its value into 2x° to find m < amc:
2x° = 2(27°) = 54°
Therefore, m < amc = 54°
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Answer:
a = 18.15
Step-by-step explanation:
Combine like terms on the left side of the equation first. Add 7 and 42, then subtract 32 from the answer you get, then subtract 32 from that answer. This is going by order of PEMDAS.
Remember PEMDAS: (numbers 3 & 4 and numbers 5 & 6 are solved from left to right)
- Parentheses
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
After combining like terms on the left side, you get -15. Now combine like terms on the right side of the equation by adding 14.3 and 7.
Get -2a alone by subtracting 21.3 from both sides.
Divide both sides by -2.
In this equation, a should equal .
Answer: The distance between the girls is 362.8 meters.
Step-by-step explanation:
So we have two triangle rectangles that have a cathetus in common, with a length of 160 meters.
The adjacent angle to this cathetus is 40° for Anna, then the opposite cathetus (the distance between Anna and the tower) can be obtained with the relationship:
Tan(A) = opposite cath/adjacent cath.
Tan(40°) = X/160m
Tan(40°)*160m = 134.3 m
Now, we can do the same thing for Veronica, but in this case the angle adjacent to the tower is 55°
So we have:
Tan(55°) = X/160m
Tan(55°)*160m = X = 228.5 m
And we know that the girls are in opposite sides of the tower, so the distance between the girls is equal to the sum of the distance between each girl and the tower, then the distance between the girls is:
Dist = 228.5m + 134.3m = 362.8m