Answer:
∠x = 90°
∠y = 58°
∠z = 32°
Step-by-step explanation:
he dimensions of the angles given are;
∠B = 32°
Whereby ΔABC is a right-angled triangle, and the square fits at angle A, we have;
∠A = 90°
∠B + ∠C = 90° which gives
32° + ∠C = 90°
∠C = 58°
∠x + Interior angle of the square = 180° (Sum of angles on a straight line)
∠x + 90° = 180°
∠x = 90°
∠x + ∠y + 32° = 180° (Sum of angles in a triangle)
90° + ∠y + 32° = 180°
∠y = 180 - 90° - 32° = 58°
∠y + ∠z + Interior angle of the square = 180° (Sum of angles on a straight line)
58° + ∠z +90° = 180°
∴ ∠z = 32°
∠x = 90°
∠y = 58°
∠z = 32°
You don't solve a quadratic equation using completing the square
Answer:
x = 5/-6 + (√13)/-6
x = 5/-6 -(√13)/-6
Step-by-step explanation:
2x^2 = -x^2 - 5x - 1. Subtract 2x^2 from both sides.
-3x^2 - 5x - 1. Do the quadratic formula.
That gives you:
-5/6 ± (√13)/-6.
Answer:
Assuming 1/20 is a 5% late fee:
$21.211
Step-by-step explanation:
67.82 x 1/20 = 3.391
67.82 + 3.391 = 71.211
Answer: 0.1357
Step-by-step explanation:
Given : Monitors manufactured by TSI Electronics have life spans that have a normal distribution with a variance of 
and a mean life span of 
hours.
Here , 
Let x represents the life span of a monitor.
Then , the probability that the life span of the monitor will be more than 14,650 hours will be :-
![P(x>14650)=P(\dfrac{x-\mu}{\sigma}>\dfrac{14650-13000}{1500})\\\\=P(z>1.1)=1-P(z\leq1.1)\ \ [\because\ P(Z>z)=1-P(Z\leq z)]\\\\=1-0.8643339=0.1356661\approx0.1357](https://tex.z-dn.net/?f=P%28x%3E14650%29%3DP%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%3E%5Cdfrac%7B14650-13000%7D%7B1500%7D%29%5C%5C%5C%5C%3DP%28z%3E1.1%29%3D1-P%28z%5Cleq1.1%29%5C%20%5C%20%5B%5Cbecause%5C%20P%28Z%3Ez%29%3D1-P%28Z%5Cleq%20z%29%5D%5C%5C%5C%5C%3D1-0.8643339%3D0.1356661%5Capprox0.1357)
Hence, the probability that the life span of the monitor will be more than 14,650 hours = 0.1357
