Answer:
An aeroplanes velocity changes from 1250m/s as it comes down to land . It accelerates at 4.9m/s² . Calculate how long it took to come to a stop ?
Step-by-step explanation:
i am sorry in never answeres ur question but pls can u help me i am struggling
cot(<em>θ</em>) = cos(<em>θ</em>)/sin(<em>θ</em>)
So if both cot(<em>θ</em>) and cos(<em>θ</em>) are negative, that means sin(<em>θ</em>) must be positive.
Recall that
cot²(<em>θ</em>) + 1 = csc²(<em>θ</em>) = 1/sin²(<em>θ</em>)
so that
sin²(<em>θ</em>) = 1/(cot²(<em>θ</em>) + 1)
sin(<em>θ</em>) = 1 / √(cot²(<em>θ</em>) + 1)
Plug in cot(<em>θ</em>) = -2 and solve for sin(<em>θ</em>) :
sin(<em>θ</em>) = 1 / √((-2)² + 1)
sin(<em>θ</em>) = 1/√(5)
Answer:
10 people lesser.
Step-by-step explanation:
Initially, it 15 people get off but 9 people get picked up, hence losing 6 people. If 4 more people get off, it has then lost 10 people total.
The original number of passengers on the bus decreased by 10 after the second stop
Assume that the total passengers on the bus before 2:30 was x
Now, at 2:30:
15 passengers got off and 9 got on.
This means that:
number of passengers = x - 15 + 9
number of passengers = x -6
10 minutes later:
4 passengers got off the bus
This means that:
number of passengers = (x-6) - 4
number of passengers = x - 10
The original number of passengers on the bus decreased by 10 after the second stop.
i think the answer is c, hope this helps ;)