Ask question

Ask question

All categories

2 years ago

5

What equation, in point-slope form, matches the graphed line shown? Question 3 options: y−5=−23(x+9) y−2=−34(x−6) y+6=45(x+3) y−

6=45(x−2)

1 answer:

ziro4ka [17]2 years ago

7 0

Step-by-step explanation:

the line passes through (6, 2) and (10, -1),

the slope =

(-1-2)/(10-6) = -3/4

the equation :

y-2 = -3/4(x -6)

You might be interested in

Solving and graphing linear equations practice Y=x+2

grin007 [14]

X=2
Y=4
There are more than 1 solution

4 0

3 years ago

Find the circumference of the circle.

LiRa [457]

I think it’s B because 3.14 times 12 is 37.68.

6 0

2 years ago

100 Points<br><br> Solve for X

bixtya [17]

A) By the rules of secants,
5(x +5) = 6(6 +4)
x + 5 = 12
x = 7

b) 3(3 +5) = 4(x +4)
6 = x +4
2 = x

5 0

2 years ago

Read 2 more answers

What is the gfc of 32 and 45?<br><br> Help me fast I’m giving out 30 points.

lisov135 [29]

Answer:

1

Step-by-step explanation:

1 can be the only thing. 2,3,4,5,6,7,8,9 don't go in 45 and 32

32/2= 16

45/2= gives a decimal

45/9= 5

32/9= gives us a decimal.

only 1 can go into both

so answer is 1

7 0

2 years ago

Read 2 more answers

Find all the zeros of the function f(x) = x^3 -2x^2 +16x -32

Alex777 [14]

Answer:

<h2>Real zeros: x = 2</h2><h2>All zeros: x = 2, x = -4i and x = 4i</h2>

Step-by-step explanation:

$f(x)=x^3-2x^2+16x-32\\\\\text{The zeros:}\\\\f(x)=0\Rightarrow x^3-2x^2+16x-32=0\\\\x^2(x-2)+16(x-2)=0\\\\(x-2)(x^2+16)=0\iff x-2=0\ \vee\ x^2+16=0\\\\x-2=0\qquad\text{add 2 to both sides}\\\boxed{x=2}\\\\x^2+16=0\qquad\text{subtract 16 from both sides}\\x^2=-16$

8 0

3 years ago