Answer:
Option: A is correct.
A) a part of a line that has one endpoint and extends indefinitely in one direction
Step-by-step explanation:
" A ray is a line that starts at a given point and goes off for ever in some direction. It may pass through another point as it does so "
Hence, option A is correct.
( The definition of Ray is:
A) a part of a line that has one endpoint and extends indefinitely in one direction )
Answer:
The second option.
Step-by-step explanation:
Let's see if this will work.
(x+24)(x-24)
Let's open the brackets
x^2 - 24x +24x - 576
= x^2 - 576
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I hope you understand. If you don't. Please, leave a comment below.
Answer:
Step-by-step explanation:
The standard equation for circle is
where point (a,b) is coordinate of center of circle and r is the radius.
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Given
center of circle =((-2,3)
let r be the radius of circle
Plugging in this value of center in standard equation for circle given above we have
Given that point (1,2 ) passes through circle. Hence this point will satisfy the above equation of circle.
Plugging in the point (1,2 ) in equation 1 we have
now we have value of r^2 = 10, substituting this in equation 1 we have
Thus complete equation of circle is
<span>A whole number is multiplied to a fraction by multiplying the whole number to numerator of the fraction while retaining the denominator of the fraction 7/8 = (7 x 1)/8 = 7 x 1/8. The number missing in the 1st blank is 7 while the number missing in the second blank is 1.</span>
Answer:
Step-by-step explanation:
To solve this problem you need the function
h(t) = -16t2 + v0t + h0
where t = time
v0 is the initial velocity, which in our case is 0
h0 = initial height, which in our case is 256
h(t) = 0 since we want to know when the ball will hit the ground.
0 = -16 t2 + 256
And we can solve for t
If we rearrange the terms we see that this is a difference of 2 squares
0 = 256 - 16t2
0 = (16-4t)(16+4t)
Setting each factor = 0
16-4t=0 16+4t=4
t = 4 t = -4
The second solution is discarded as time cannot be negative.
So the ball will hit the ground in 4 seconds.